Answer:
- a) 125,220,046 barrels
- b) 71.25 years
Step-by-step explanation:
<u>Oil consumption:</u>
<u>Rate of increase of consumption:</u>
<u>Total reserves </u>
- 155*2000000 = 310000000 barrels
a) ....................................................................................
<u>Total oil consumption at the end of 42 years:</u>
- 2,000,000
- 2,000,000*1.02 =
- 2.000,000*1.02^2
- ...
- 2,000,000*1.02^41
<u>Sum</u>:
- 2000000*(1 + 1.02+ 1.02^2+ ...+ 1.02^41) =
- 2000000*(1.02^41 - 1)/(1.02 - 1) = 125,220,046 barrels
b) ....................................................................................
<u>Oil reserves will last:</u>
- 2000000*(1.02^x - 1)/(1.02 - 1) = 310000000
- (1.02^x - 1)/0.02 = 155
- 1.02^x - 1 = 155*0.02
- 1.02^x =1 +3.1
- 1.02^x = 4.1
- x log 1.02 = log 4.1
- x = log 4.1 /log 1.02
- x = 71.25 years
In rectangle, all the angles are 90°. ∠M =∠N = ∠O = ∠P = 90°. Therefore 2X - 10 = 90 and 3Y + 9 = 90. Therefore X = 50 and Y = 27. So option B is correct.
Triangle ABF has base 10 and height 3, so area (1/2)*10*3 = 15.
Trapezoid EBCD has bases 6 and 7 and height 6, so area
.. (6+7)*6/2 = 39
The total area of the figure is
.. 15 +39 = 54 . . . . . square units
Answer:

Step-by-step explanation:
We are given that
Radius of end of a log, r= 9 in
Error,
in
We have to find the error in computing the area of the end of the log by using differential.
Area of end of the log, A=


Now,
Approximate error in area

Using the values


Hence, the possible propagated error in computing the area of the end of the log
"help the number ... ?"
6x ≥ 8x-4
Then 4≥2x, or 2≥x, or x≤2.