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LenaWriter [7]
2 years ago
10

What is the value of the x variable in the solution to the following system of equations? (5 points) 2x − 3y = 3 5x − 4y = 4 Sel

ect one: a. −1 b. 0 c. x can be any number as there are infinitely many solutions to this system d. There is no x value as there is no solution to this system
Mathematics
1 answer:
Rama09 [41]2 years ago
8 0

Answer:

D. There is no x value as there is no solution to this system

Step-by-step explanation:

2x − 3y = 3                                  5x − 4y = 4

5x - 4y = 4               -4y = -5x + 4                         y = 5/4x - 1

2x - 3(5/4x - 1) = 3

2x - 15/4x + 3 = 3

-7/4x = 0

x = 0

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Andrea earns $32.25 a day. After 9 days, about how much will she have earned?
Zanzabum

Answer:

290.25 dollars earned

Step-by-step explanation:

32.25 times 9

8 0
3 years ago
Read 2 more answers
Solve 7x - 5 = 2 ????????????????
wolverine [178]
<span>7x - 5 = 2
add 5 to both sides
</span><span>7x - 5+5 = 2+5

7x=7  
Divide both sides by 7 to get x by itself
x=1 </span>
4 0
3 years ago
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The cost of oranges in a grocery store is directly proportional to the number of oranges purchased. Jerri payed $2.52 for 6 oran
ExtremeBDS [4]

Answer: option A is the correct answer.

Step-by-step explanation:

The cost of oranges in a grocery store is directly proportional to the number of oranges purchased. Jerri paid $2.52 for 6 oranges.

If p represents the cost, in dollars,and n represents the number of oranges purchased, then introducing a proportionality constant, k, the equation becomes

p = kn

2.52 = k × 6

k = 2.52/6 = 0.42

Therefore, the equation representing the relationship is

p = 0.42n

4 0
3 years ago
You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll
Misha Larkins [42]

Answer:

a. P (R3 | G1)=\frac{1}{5}

b. P (R6| G3)= \frac{1}{3}

c. P(G3|E)=\frac{2}{3}

d. P (E|G3)=\frac{2}{3}

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}

6 0
3 years ago
Who knows how to do this ​
IgorC [24]

Answer:

<h2>144 {cm}^{2}</h2>

Step-by-step explanation:

Given,

As we know that the all sides of the square are equal.

Length of a square paper = 12 cm

Area of square = ?

Now, let's find the area of square

=  {l}^{2}

plugging the value of length,

{(12)}^{2}

Evaluate the power

= 144 square cm

Hope this helps...

Best regards!!

7 0
3 years ago
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