Answer:
Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.
Given: △ABC, m∠B=90°
Find: AC and BK.
Short leg 90 degrees Long leg Hypotenuse
AB=12 90 BC=16 AC= ?
AK = ? 90 BK = ? AB=12
AC = SQRT (AB*AB + BC*BC) = 20 [right triangle; Pythagorean Theorem]
Similar triangles:[Note: In diagram, share two angles. Therefore share three angles]
BK / 16 = AB / AC
BK / 16 = 12 / 20
BK = (3/5)16
BK = 48/5
another answer let see this
AB^2+BC^2=AC^2
12^2+16^2=AC^2
144+256=AC^2
400=AC^2
20=AC
# be careful#
Answer:
d
Step-by-step explanation:
2
- 7
= 4
- 7
= Since, we have same bases, we can subtract!
= To get,
=
-3 Answer
Answer:
7
Step-by-step explanation:
σ = 4 ; μ =?
8.52 to the left of X
.
P(X < 8.52) = 64.8%
P(X < 8.52) = 0.648
Using the Z relation :
(x - μ) / σ
P(Z < (8.52 - μ) / 4)) = 0.648
The Z value of 0.648 of the lower tail is equal to 0.38 (Z probability calculator)
Z = 8.52 - μ / 4
0.38 = 8.52 - μ / 4
0.38 * 4 = 8.52 - μ
1.52 = 8.52 - μ
μ = 8.52 - 1.52
μ = 7
True because the center is (2,1) and radius is 2
