We have been given that the profit that the vendor makes per day by selling x pretzels is given by the function $P(x)=-4x^2+2400x-400$ . We are asked to find the number of pretzels that must be sold to maximize profit.

First of all, we will find the derivative of our given function.

$P'(x)=-4\cdot 2x^{2-1}+2400$

$P'(x)=-8x+2400$

Now, we will find the critical point by equating derivative with 0 as:

$-8x+2400=0$

$-8x+2400-2400=0-2400$

$-8x=-2400$

$\frac{-8x}{-8}=\frac{-2400}{-8}$

$x=300$

Therefore, the company must sell 300 pretzels to maximize profit and option B is the correct choice.

8 0

3 years ago

Enter the value of ( – 8)(15)( - 1/2) A 60 B - 60 С 240 D -240

Harman [31]

Answer: A 60
Explanation

4 0

3 years ago

If 4x - 7 is one angle and 2x + 13 is another, then what is the sum of both angles?

Aleksandr [31]

Answer:56

Step-by-step explanation:fydtif7oujhgcfdker87tiugjhfbdgr79tkujmgnb

8 0

4 years ago