Hypoventilation dramatically increases carbonic acid concentration and involves________?
1 answer:
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Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
=
= 10 m/s
<span><u>Note that this one is the final velocity.</u></span><u />
We also know that,
initial velocity (u) = 0 m/s .......<span> because the car starts from rest.
</span>Now,
=
=
= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....<span>note that displacement is same as distance.
</span><span> = 1200 N * 100 m
</span> = 120000 N.m
= 120000 J
Now,
Power (P) =
=
= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
=
= 10 m/s
<span><u>Note that this one is the final velocity.</u></span><u />
We also know that,
initial velocity (u) = 0 m/s .......<span> because the car starts from rest.
</span>Now,
=
=
= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....<span>note that displacement is same as distance.
</span><span> = 1200 N * 100 m
</span> = 120000 N.m
= 120000 J
Now,
Power (P) =
=
= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.
Answer:
v = 5.75 x 10⁶ m/s
Explanation:
The radius (r) of the circular orbit taken by a charged particle is related to its speed perpendicular to a magnetic field of strength B, and is given by
r = --------------(i)
Where,
q = charge of the particle
m = mass of the particle
Making v subject of the formula in equation (i) above gives
v = -------------------(ii)
Given;
r = 20cm = 0.2m
B = 0.3T
v = unknown
q = charge of proton = 1.6 x 10⁻¹⁹ C
m = mass of the proton = 1.67 x 10⁻²⁷kg
Substitute the values of m, q, B and r into equation (ii) above to get;
v =
Solving for v gives:
v = 5.75 x 10⁶ m/s
Therefore, the velocity of the proton is 5.75 x 10⁶ m/s