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zmey [24]
3 years ago
15

Hypoventilation dramatically increases carbonic acid concentration and involves________?

Physics
1 answer:
sveta [45]3 years ago
8 0
Extremely slow breathing
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. (a) How long can you play tennis on the 800 kJ (about 200 kcal) of energy in a candy bar? (b) Does this seem like a long time?
galina1969 [7]

(a). The power of the candy bar is,

P=440\text{ W}

The time taken to play on 800 kJ energy of the candy bar is,

t=\frac{E}{P}

where E is the energy.

Substituting the known values,

\begin{gathered} t=\frac{800\times10^3}{440} \\ t=1.818\times10^3\text{ s} \\ t=1818\text{ seconds} \end{gathered}

As 1 minute is equal to 60 seconds,

Thus,

\begin{gathered} t=1818\text{ seconds} \\ t=\frac{1818}{60} \\ t=30.3\text{ min} \end{gathered}

Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.

(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.

The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.

8 0
1 year ago
HELPP ITS DUE IN 5 MINUTES FREE BODY DIAGRAMS
Rashid [163]

Answer:

C i think sorry if inmccorect

Explanation:

5 0
3 years ago
Read 2 more answers
Which type of electromagnetic radiation is most likely to be ionizing
zlopas [31]

Answer:

Xrays. i hope that helps

Explanation:

4 0
3 years ago
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An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster.
Dmitry [639]

Answer:

640 J

640 J

Explanation:

ΔKE = ½ mv² − ½ mu²

ΔKE = ½ m (v² − u²)

ΔKE = ½ (80 kg) ((5 m/s)² − (3 m/s)²)

ΔKE = 640 J

Work = ΔE

Work = 640 J

5 0
3 years ago
Read 2 more answers
A 6.4-N force pulls horizontally on a 1.5-kg block that slides on a smooth horizontal surface. This block is connected by a hori
Elena L [17]

-- Although it's not explicitly stated in the question,we have to assume that
the surface is frictionless.  I guess that's what "smooth" means.

-- The total mass of both blocks is (1.5 + 0.93) = 2.43 kg. Since they're
connected to each other (by the string), 2.43 kg is the mass you're pulling.

-- Your force is 6.4 N.
                                    Acceleration = (force)/(mass) = 6.4/2.43 m/s²<em>
                                                                 </em>
That's about  <em>2.634 m/s²</em>  <em>

</em>
(I'm going to keep the fraction form handy, because the acceleration has to be
used for the next part of the question, so we'll need it as accurate as possible.)

-- Both blocks accelerate at the same rate. So the force on the rear block (m₂) is

       Force = (mass) x (acceleration) = (0.93) x (6.4/2.43) = <em>2.45 N</em>.

That's the force that's accelerating the little block, so that must be the tension
in the string.


7 0
3 years ago
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