The center of mass of a 0.3 kg (non-uniform) meter stick is located at its 46-cm mark. What is the magnitude of the torque (in N
1 answer:
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Answer:
Density of 127 I =
Also,
Explanation:
Given, the radius of a nucleus is given as
.
where,
- A is the mass number of the nucleus.
The density of the nucleus is defined as the mass of the nucleus M per unit volume V.
For the nucleus 127 I,
Mass, M =
Mass number, A = 127.
Therefore, the density of the 127 I nucleus is given by
On comparing with the density of the solid iodine,
Answer: d. 8.25 m/s
Explanation:
We are given that Current= 5 m/s in j direction
Velocity= 8 m/s i + 3 m/s j
Now, we have to find Jada's speed with respect to the water.
First we find Jada's velocity with respect to water
v= (8 i + 3 j) - (5 j)
v= 8i - 2 j
To find the speed, we take the magnitude of this velocity vector we have
|v|=
|v|= = 8.246 m/s
which comes out to be around = 8.25 m/s
So option d is correct.