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dolphi86 [110]
3 years ago
5

A bar magnet moves through a loop of wire with constant velocity, and the north pole enters the loop first the induced current w

ill be greatest when the magnet is located so that the loop is
Physics
2 answers:
Ksivusya [100]3 years ago
8 0
<span>A bar magnet moves through a loop of wire with constant velocity, and the north pole enters the loop first the induced current will be greatest when the magnet is located so that </span>the loop is near either the north or the south pole.
noname [10]3 years ago
3 0

Answer:

Loop must be near the end of the pole of bar magnet

Explanation:

As we know by Faraday's law of electromagnetic induction the induced EMF or induced current in the loop is given by

EMF = \frac{d\phi}{dt}

here we know that

\phi = B.A

now we know that as the magnet comes closer to the loop the magnetic field due to any of the pole of magnet will increase.

So here the maximum flux will pass through the magnet when magnet is closer to the loop.

So here when A bar magnet moves through a loop of wire with constant velocity, and the north pole enters the loop first the induced current will be greatest when the magnet is located so that the loop is when Loop must be near the end of the pole of bar magnet

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Marie curie was a scientist who won two nobel prizes in the early 1900s for her work with.
Arada [10]

She remains the only person to be honored for accomplishments in two separate sciences. Curie received the Nobel Prize in Physics in 1903, <u>along with her husband and Henri Becquerel, </u>for their work on radioactivity.

<h3>What did Marie Curie discover?</h3>

Relentless regardless of a vocation of truly requesting and at last lethal work, she found polonium and radium, supported the utilization of radiation in medication and essentially changed how we might interpret radioactivity. Curie was conceived Marya Skłodowska in 1867 in Warsaw.

  • Curie was the first person to win two Nobel Prizes.
  • She managed it all without a fancy lab.
  • Nobel Prizes were a family affair.
  • Curie was the first female professor at Sorbonne University.
  • Curie is buried in the Panthéon in Paris.

To learn more about Marie Curie from the given link

brainly.com/question/1160057

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4 0
1 year ago
Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

    I₂ = 75.5 / cos² 45.8

    I₂ = 155.3 W

We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

   I₁ = 181.2 W

Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
4 years ago
A 0.40-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so
lubasha [3.4K]

Answer:

160N/m

Explanation:

According to Hooke's law which states that the extension of an elastic material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

k is the spring constant

e is the extension

From the formula k = F/e

Since the body accelerates when the block is released, F = ma according to Newton's second law of motion.

The spring constant k = ma/e where

m is the mass of the block = 0.4kg

a is the acceleration = 8.0m/s²

e is the extension of the spring = 2.0cm = 0.02m

K = 0.4×8/0.02

K = 3.2/0.02

K = 160N/m

The spring constant of the spring is therefore 160N/m

4 0
4 years ago
How does absorption spectra occur?
Arlecino [84]

An absorption spectrum occurs when light passes through a cold, dilute gas and atoms in the gas absorb at characteristic frequencies; since the re-emitted light is unlikely to be emitted in the same direction as the absorbed photon, this gives rise to dark lines (absence of light) in the spectrum.

hope this helped :)

mark brainliest

3 0
4 years ago
Consider the differential equation
Zielflug [23.3K]
Yp(t) = A1 t^2 + A0 t + B0 t e(4t)

=> y ' = 2A1t + A0 + B0 [e^(4t) +4 te^(4t) ]

     y ' = 2A1t + A0 + B0e^(4t) + 4B0 te^(4t)

=> y '' = 2A1 + 4B0e(4t) + 4B0 [ e^(4t) + 4te^(4t)

     y '' = 2A1 + 4B0e^(4t) + 4B0e^(4t) + 16B0te^(4t)

Now substitute the values of y ' and y '' in the differential equation:

 
<span>y′′+αy′+βy=t+e^(4t)


</span> 2A1 + 4B0e^(4t) + 4B0e^(4t) + 16B0te^(4t) + α{2A1t + A0 + B0e^(4t) + 4B0 te^(4t) } + β{A1 t^2 + A0 t + B0 t e(4t)} = t + e^(4t)

Next, we equate coefficients

1) Constant terms of the left side = constant terms of the right side:

2A1+ 2αA0 = 0 ..... eq (1)

2) Coefficients of e^(4t) on both sides

8B0 + αB0 = 1 => B0 (8 + α) = 1 .... eq (2)

3) Coefficients on t

2αA1 + βA0 = 1 .... eq (3)


4) Coefficients on t^2

βA1 = 0 ....eq (4)

given that A1 ≠ 0 => β =0

5) terms on te^(4t)

16B0 + 4αB0 + βB0 = 0 => B0 (16 + 4α + β) = 0 ... eq (5)

Given that B0 ≠ 0 => 16 + 4α + β = 0

Use the value of β = 0 found previously

16 + 4α = 0 => α = - 16 / 4 = - 4.

Answer: α = - 4 and β = 0
  




3 0
4 years ago
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