1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ahat [919]
4 years ago
12

Research is done before or after a hypothesis is written

Physics
1 answer:
weqwewe [10]4 years ago
7 0
Research is done before a hypothesis. You would need to know more about your topic before making a guess
You might be interested in
A piston–cylinder device initially contains 2 L of air at 100 kPa and 25°C. Air is now compressed to a final state of 600 kPa an
bagirrra123 [75]

Answer:

a. The energy of the air at the initial and the final states is 0kJ and 0.171kJ respectively

b. 0.171kJ

c. 0.143

Explanation:

a.

Because there are same conditions of the state of air at the surroundings and at the Initial stage, the energy of air at the Initial stage is 0kJ.

Calculating energy at the final state;

We start by calculating the specific volume of air in the environment and at the final state.

U2 = At the final state, it is given by

RT2/P2

U1= At the Initial state, it is given by

RT1/P1

Where R = The gas constant of air is 0.287 kPa.m3/kg

T2 = 150 + 273 = 423K

T1 = 25 + 273 = 298K

P2 = 600KPa

P1 = 100KPa

U2 = 0.287 * 423/600

U2 = 0.202335m³/kg

U1 = 0.287 * 298/100

U1 = 0.85526m³/kg

Then we Calculate the mass of air using ideal gas relation

PV = mRT

m = P1V/RT1 where V = 2*10^-3kg

m = 100 * 2 * 10^-3/(0.287 * 298)

m = 0.00234kg

Then we calculate the entropy difference, ∆s. Which is given by

cp2 * ln(T2/T1) - R * ln(P2/P1)

Where cp2 = cycle constant pressure = 1.005

∆s = 1.005 * ln (423/298) - 0.287 * ln(600/100)

∆s = -0.1622kJ/kg

Energy at the final state =

m(E2 - E1 + Po(U2 - U1) -T0 * ∆s)

E2 and E1 are gotten from energy table as 302.88 and 212.64 respectively

Energy at the final state

= 0.00234(302.88 - 212.64 + 100(0.202335 - 0.85526) - 298 * -0.1622)

Energy at the final state = 0.171kJ

b.

Minimum Work = ∆Energy

Minimum Work = Energy at the final state - Energy at the initial state

Minimum Work = 0.171 - 0

Minimum Work done = 0.171kJ

c. The second-law efficiency of this process is calculated by ratio of meaningful and useful work

= 0.171/1.2

= 0.143

3 0
3 years ago
What happens to electron flow with a conductor of the voltage source is removed?
9966 [12]
The electrons stop flowing
4 0
3 years ago
A mass of 4kg suspended by a light string 2m long and at rest is projected horizontally with a velocity of 1.5 m/s. find the ang
Dafna11 [192]

Answer:

19.5°

Explanation:

The energy of the mass must be conserved. The energy is given by:

1) E=\frac{1}{2}mv^2+mgh

where m is the mass, v is the velocity and h is the hight of the mass.

Let the height at the lowest point of the be h=0, the energy of the mass will be:

2) E=\frac{1}{2}mv^2

The energy when the mass comes to a stop will be:

3) E=mgh

Setting equations 2 and 3 equal and solving for height h will give:

4) h=\frac{v^2}{2g}

The angle ∅ of the string with the vertical with the mass at the highest point will be given by:

5) cos\phi=\frac{l-h}{l}

where l is the lenght of the string.

Combining equations 4 and 5 and solving for ∅:

6) \phi={cos}^{-1}(\frac{l-h}{l})={cos}^{-1}(1-\frac{h}{l})={cos}^{-1}(1-\frac{v^2}{2gl})

8 0
4 years ago
If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take
viva [34]

Answer:

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

T = \sqrt{\frac{4\pi^2r^3 }{GM} }

where r = radius of orbit of Hubble Space Telescope

G = gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

M = Mass of earth

We are given that:

r = radius of the earth + distance of HST from earth

r = 6.38 * 10^6 + 598 = 6380598 m

M = 5.98 * 10^{24} kg

Therefore, T will be:

T = \sqrt{\frac{4*\pi^2 * 6380598^3 }{6.67408 * 10^{-11} * 5.98 * 10^{24}}}

T = 5069.04 secs

The orbital period of the Hubble Space Telescope is 5069.04 seconds.

7 0
3 years ago
Read 2 more answers
A 200 kg roller coaster is located at the top of a hill where the height is 30 m. What is the velocity when it reches the bottom
maw [93]

Assuming it starts at rest, the roller coaster only has potential energy at the top of the hill, which is

E_P=(200\,\mathrm{kg})(30\,\mathrm m)g

When it reaches the bottom, its potential energy will have converted to kinetic energy,

E_K=\dfrac12(200\,\mathrm{kg})v^2

where v is its velocity at that point. By the law of conservation of energy, assuming no loss of energy due to other sources (e.g. sound, heat), we have

E_P=E_K\iff(6000\,\mathrm{kg}\cdot\mathrm m)g=(100\,\mathrm kg})v^2

\implies v=\sqrt{60g}\,\dfrac{\rm m}{\rm s}\approx24.2\,\dfrac{\rm m}{\rm s}

8 0
4 years ago
Read 2 more answers
Other questions:
  • Two people of different masses sit on a seesaw. M1, the mass of person 1, is 91 kg, M2 is 45 kg, d1 = 0.8 m, and d2 = 1.1 m. The
    14·1 answer
  • A car travels at a constant speed of 60 KM/H for three hours. What is the total distance the car traveled?
    8·2 answers
  • When you squeeze spring coils together then release them, you are creating a ______ wave.
    15·1 answer
  • f a force of 2020 newtons​ [N] is applied to a surface and the pressure is measured as 4 comma 5004,500 pascals​ [Pa], what is t
    6·1 answer
  • A toy rocket travels at an initial velocity of 144 feet per second. The height of the rocket can be modeled by the function h(t)
    12·1 answer
  • Which statement best describes how energy transfer within earths atmosphere 10 affect a weather condition? A)during radiation ob
    13·1 answer
  • The strength of the force of gravity depends on
    6·1 answer
  • Q) Suppose, you are in a sporting event. You notice that everyone stands up when it’s his turn,
    15·1 answer
  • 4. Where would a tsunami be most likely to occur?
    5·1 answer
  • When friction slows a sliding block___
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!