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Ahat [919]
3 years ago
12

Research is done before or after a hypothesis is written

Physics
1 answer:
weqwewe [10]3 years ago
7 0
Research is done before a hypothesis. You would need to know more about your topic before making a guess
You might be interested in
A 86 kg human stands on the surface of Venus. The mass of Venus is 4.9 × 1024 kg and its radius is 6.1 × 106 m. Collapse questio
iris [78.8K]

Answer:

755.37 N

Explanation:

We are given that

Mass of venus=m_1=4.9\times 10^{24}kg

Radius=r=6.1\times 10^6m

Mass of human=m_2=86 kg

We know that the gravitational force between two bodies

F=G\frac{m_1m_2}{r^2}

Where G=Gravitational constant=6.67\times 10^{-11}Nm^2/kg^2

Using the formula

The magnitude of the gravitational force exerted by Venus on the human=F=\frac{6.67\times 10^{-11}\times 86\times 4.9\times 10^{24}}{(6.1\times 10^6)^2}

The magnitude of the gravitational force exerted by Venus on the human=F=755.37N

7 0
3 years ago
The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 gra
DerKrebs [107]

1,000 grams = 1 kilogram
20 grams = 0.02 kilogram

Kinetic energy = (1/2) (mass) x (speed)²

                           (1/2) (0.02) x (15)² =

                                 (0.01)  x  (225)  =  2.25 joules
 
4 0
3 years ago
Read 2 more answers
What is the answer for this question (4x³)²​
Delvig [45]
16x to the power of 6
6 0
3 years ago
Read 2 more answers
An insulated beaker with negligible mass contains 0.250 kg of water at 75.0C. How many kilograms of ice at -20.0C must be droppe
kkurt [141]

Answer:

The amount of kilograms of ice at -20.0°C that must be dropped into the water to make the final temperature of the system 40.0°C = 0.0674 kg

Explanation:

Heat gained by ice in taking the total temperature to 40°C = Heat lost by the water

Total Heat gained by ice = Heat used by ice to move from -20°C to 0°C + Heat used to melt at 0°C + Heat used to reach 40°C from 0°C

To do this, we require the specific heat capacity of ice, latent heat of ice and the specific heat capacity of water. All will be obtained from literature.

Specific heat capacity of ice = Cᵢ = 2108 J/kg.°C

Latent heat of ice = L = 334000 J/kg

Specific heat capacity of water = C = 4186 J/kg.°C

Heat gained by ice in taking the total temperature to 40°C = mCᵢ ΔT + mL + mC ΔT = m(2108)(0 - (-20)) + m(334000) + m(4186)(40 - 0) = 42160m + 334000m + 167440m = 543600 m

Heat lost by water = mC ΔT = 0.25 (4186)(75 - 40) = 36627.5 J

543600 m = 36627.5

m = 0.0674 kg = 67.4 g of ice.

3 0
3 years ago
I'm not really sure how to go about creating the equation, can anyone help me?
AlexFokin [52]
The displacement vector (SI units) is
\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}

The speed is a scalar quantity. Its magnitude is
v= \sqrt{A^{2}t^{2}+A^{2}(t^{3}-6t^{2})^{2}} \\ v=A \sqrt{t^{2}+t^{6}-12t^{5}+36t^{4}} \\ v=At \sqrt{t^{4}-12t^{3}+36t^{2}+1}

Answer: At√(t⁴ - 12t³ + 36t² + 1)
3 0
3 years ago
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