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nikdorinn [45]
3 years ago
9

In the nucleus of all atoms are sub-atomic particles called protons and neutrons. all protons have a positive charge. since all

like-charged particles repel each other, you would logically conclude that protons could not stay in close proximity to each other in an atom's nucleus. how do you explain the fact that protons stay close together in the nucleus?
Physics
1 answer:
murzikaleks [220]3 years ago
6 0

Protons stay close together in the nucleus because the strong nuclear force.


There are four natural elemental forces: 1) gravity, 2) electromagnetic force, 3) weak nuclear force, and 4) strong nuclear force.


Gravity is an attractive force. It acts at long distance and is proportion to the product of the masses. It is not relevant in the nucleous of an atoms because the masses are tiny.


Electrotmagnetic force may be attractive or repulsive. Indeed, as stated since the protons have all positive charge, this force is repulsive, and you could expect that they the protons cannot stand so close to each other in the nucleous.


Strong nuclear force is the strongest of the four forces in nature and acts only to very short distances. It is the atractive force between the partilces in the atom nuclei. This force overcomes the electromagnetic repulsion between the protons. This force is responsible for keeping the protons and the neutrons together in the nuclei.

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Use the concepts of kinetic energy and potential energy to describe the motion of a child on a swing. Why does the child need a
andrew-mc [135]
When the child is moving, he/she has kinetic energy. For just a brief second before they move the other way, the child is not moving, but they have gravitational potential energy.

The child may need a push from time to time because friction with the air causes loss of energy.
4 0
2 years ago
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A 72-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.61 m,
chubhunter [2.5K]

Answer:

2849.98 J

Explanation:

From the question,

Work done by the boy = change Potential energy of the boy + change in kinetic energy of the boy

W = ΔP + ΔK..................... Equation 1

Where W = work done by the boy, ΔP = change in potential energy of the boy, ΔK = Change in kinetic energy of the boy.

But,

ΔP = mgΔh.................... Equation 2

ΔK = 1/2mΔv²................. Equation 3

Where m = mass of the boy, Δh = change in height of the boy, Δv = change in velocity of the boy.

Substitute equation 2 and 3 into equation 1

W = mgΔh+1/2mΔv²................. Equation 4

Given: m = 72 kg, Δh = 1.61 m, Δv = 8.5-1.6 = 6.9 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 72(9.8)(1.61)+1/2(72)(6.9²)

W = 1136.016+1713.96

W = 2849.98 J

8 0
3 years ago
Why must lslamic believers travel to Mecca once during their lives?
SSSSS [86.1K]

Answer: The Islamic believers traveled to Mecca once during their lives because they would perform Hajj ( this is piligrimage) and it is the main part of the islam

Explanation:

Hajj is very important to islam people so in order to do this they had to go to Mecca. Hajj is rituals and rites that need to be fulfilled. Its not the only pillar for islam but it is one out of five.

4 0
3 years ago
The net external force on a golf cart is 411 N north of tha cart has a total mass of 281 kg what is tha cart acceleration
Alisiya [41]

1.46m/s²

Explanation:

Given parameters:

Mass of cart = 281kg

Net external force = 411N

Unknown:

Acceleration of the cart = ?

Solution:

According to newton's second law " the net force on a car is the product of its mass and acceleration";

            Force = mass x acceleration

Since acceleration of the cart is unknown;

     Acceleration = \frac{force}{mass} = \frac{411}{281}

  Acceleration = 1.46m/s²

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

8 0
3 years ago
Two long, straight wires are parallel and 20 cm apart. One carries a current of 2.2 A, the other a current of 5.9 A. (a) If the
Leya [2.2K]

Answer: 1.298\times 10^{-5}\ N/m

Explanation:

Given

Current in the first wire I_1=2.2\ A

Current in the second wire I_2=5.9\ A

wires are 20\ cm apart

Force per unit length between the current-carrying wires is

\Rightarrow \dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi r}

Force exerted  by the wires is the same

Put the values

\Rightarrow \frac{F}{l}=f=\dfrac{4\pi \times 10^{-7}\times 2.2\times 5.9}{2\pi \times 0.2}=1.298\times 10^{-5}\ N/m

This force will be repulsive in nature as the current is flowing opposite

4 0
3 years ago
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