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Ludmilka [50]
3 years ago
10

What is average speed of someone driving 558 miles in 9 hours?

Mathematics
1 answer:
barxatty [35]3 years ago
4 0
That would be 558 / 9 = the answer
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Please help me i would appreciate it greatly
Lera25 [3.4K]

Answer:

I would put B

Sorry if it's wrong I would have to know what the test is about to answer this

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
16 paise into rupees ​
denis-greek [22]

Answer:

0.16

Step-by-step explanation:

1paise = 1/100rupee

so, 16 paise = 16/100

16/100= 0.16

7 0
2 years ago
How many of the 100 bin A items can be recycled at a specialized center?
pentagon [3]
Depending on how big the center is, I would say 15.
I hope this helped!
3 0
3 years ago
Could someone help with the questions in the images below? I found them difficult
zubka84 [21]
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
120/4 = 30
30 x 3 = 90
Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
Again, by the looks of it, the Maximum value is 8.5.

Now you have all the data needed for the box plot.

Min = 0
LQ = 0.8
Med = 2.1
UQ =  3
Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
Draw a line (using  ruler) across at 20 until you reach the line.
Draw another one down to help you read the number.
The median looks like 34 seconds.
Question 4b - For this question, we already know the Min, Med and Max. Now we must work out the LQ and UQ.

Remember, LQ = n/4
In this case, n = 40
40/4 = 10
Look across at ten and you will find that the LQ = 16 seconds

To work out the UQ, we multiply the LQ place by 3 3(n/4).
3 x 10 = 30
30 on the graph takes us up to 45 seconds.

We now know that the:
Min = 9
LQ = 16
Med = 34
UQ = 45
Max = 57

With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
The Inter Quartile Range is the difference between the Upper Quartile and the Lower Quartile (how wide the box is).
The boy IQR = 45 - 16 = 29
The girls IQR = 34 - 23 = 11
Again, the girls have much more concise results; even though they did not get the quickest result, they were more like one another.

Question 5a - The median in a box plot is always the line down the centre of the box. In this case:
Median = 24 marks
Question 5b - The IQR is always the UQ - LQ
With this data, the IQR is the following:
36 - 17 = 19 marks

Hope this helps
6 0
3 years ago
Liz is using the distributive property to evaluate the expression 27(36) by using friendlier numbers. Her work is shown below.
Katen [24]
Liz attempted to factor 36. Since 36 = 3*12 and not 3+12, this is not the way to go. In stead of factoring 36, she should have split it into a friendly sum, like 36=30+6.

Then Step 1 should have been 27(6+30).
4 0
3 years ago
Read 2 more answers
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