Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)
Answer:
Step-by-step explanation:
Two angles are Adjacent when they have a common side and a common vertex (corner point) and don't overlap.
This is ur answer although remember to simplify
Answer:
can't be factored
Step-by-step explanation:
remember the method of factoring
- Find two numbers that multiply to give ac and add to give b.
- Rewrite the middle with those numbers
- Factor the first two and last two terms separately
let's try to do the first step
to figure out b we two factor of 10 that add up to -3
factor of 10:
likewise
as you can see there's no factor that add up to -3 and multiply to give 10
hence,
the expression can't be factored
Answer:
261.67 
Step-by-step explanation:
The formula is 1/3 