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Law Incorporation [45]
2 years ago
8

Help plsssssss someone

Mathematics
2 answers:
Ede4ka [16]2 years ago
6 0

Answer:

672

Step-by-step explanation:

oksano4ka [1.4K]2 years ago
3 0
The answer would be C.
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A 50 meter path surrounds a rectangular garden . The width of the garden is two-thirds its length. find its area.
astra-53 [7]
w-width\\l-length\\\\2w+2l=50\to w+l=25\\w=\frac{2}{3}l\\\\substitute:\\\\\frac{2}{3}l+l=25\\\\\frac{5}{3}l=25\ \ \ \ /\cdot\frac{3}{5}\\\\l=15\ (m)\\\\w=\frac{2}{3}\cdot15=10\ (m)\\\\Area:A_{\fbox{ }}=wl\to A_{\fbox{ }}=10\cdot15=150\ (m^2)
7 0
2 years ago
What is 10+10/10? Please Help ​
Andreyy89

Answer:

11

Step-by-step explanation:

10+1=11

Hope that helps ;)

3 0
3 years ago
Read 2 more answers
Let me know if you can see the expression if not I will just type it.​
faltersainse [42]

Answer:

-15x+24

Step-by-step explanation:

You can write that as:

(-6x+36)-(12x-3x+12)\\-6x+36-12x+3x-12\\-15x+24

8 0
3 years ago
Solve for x. 8(9x-4)-2=3+2
gavmur [86]
So first you have to move the -2 over to the opposite side.
8(9x-4)=3+2+2
Then you can simplify the right side 
8(9x-4)=7
Then you distribute
8*9x=72x
8*-4=-32
so now you have...
72x-32=7
Then you move the 37 over
72x=39
Then you divide by 72 to isolate x
x=39/72 or x= 13/24 or <span>x=0.54167</span>
6 0
2 years ago
Please help me its about solving system by substitution
Andrew [12]

Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = -x + 1

2x + 3y = 6

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    2x + 3(-x + 1) = 6
  2. Distribute 3:                         2x - 3x + 3 = 6
  3. Combine like terms:           -x + 3 = 6
  4. Isolate <em>x</em> terms:                   -x = 3
  5. Isolate <em>x</em>:                              x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                     y = -x + 1
  2. Substitute in <em>x</em>:                        y = -(-3) + 1
  3. Simplify:                                   y = 3 + 1
  4. Add:                                         y = 4
6 0
2 years ago
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