The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
According to the given question.
The total number of elements, n = 3
The number of elements to be selected at a time when repetition is allowed, r = 5
Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is
.
Therefore,
The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed
= 
= 243
Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.
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Answer:C
Step-by-step explanation:i would say C because its not a negative and it dosent go up 2 let me know if im wrong
Answer:
D. ASA
Step-by-step explanation:
In triangles ABC and ADC,
- Angles BCA and DAC are congruent (from the diagram);
- Angles BAC and DCA are congruent (from the diagram);
- AC is congruent AC (by reflexive property).
So, the triangles ABC and CDA are congruent by ASA postulate.
ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.
115.20 is 20% of 576
576 x .20 = 115.20
Answer: 3(2 • (2x))
Explanation:
6 • 2(3x)
6 • 6x
3(2 • (2x))