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ArbitrLikvidat [17]
2 years ago
5

Please hurry!

Mathematics
2 answers:
RoseWind [281]2 years ago
6 0

Answer:

BC= 16 cm

CD= Cannot Be Determined.

ED= 10 cm

BE= 14 cm

Step-by-step explanation:

aksik [14]2 years ago
3 0

Answer:

D should be in (8, -4)

Step-by-step explanation:

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Evaluate A/B for a = 1/2 and b = -3/7
bonufazy [111]

Answer:

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Step-by-step explanation:

If a = 1/2 and b = -3/7, then your given:

1/2 divided by -3/7=

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3 years ago
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The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

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297 x 65 two step problem dotted line
labwork [276]

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Step-by-step explanation:

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