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3 years ago

11

What is the reading in kwhr of the electric meter shown in the exam figure below?

1 answer:

just olya [345]3 years ago

7 0

We can't tell, because you won't let us SEE
the electric meter shown in the exam figure.

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Help me. I need it lol

Salsk061 [2.6K]

Answer: Choice C

The probability of getting all heads is the same as the probability of getting all tails

=========================================================

Explanation:

H = heads

T = tails

In the first row, we have HHH to signify three heads. This shows up 1 time out of 8 outcomes total (each row is a different outcome). The probability of getting HHH is 1/8.

In the last row, TTT means we got three tails. Like with HHH, it only shows up once out of eight times, so the probability of getting TTT is 1/8 as well.

Therefore, both HHH and TTT have the same probability. This is because both sides of the coin have equal chances to land on. If the coin was more biased toward heads for example, then HHH and TTT would have different probabilities.

7 0

3 years ago

Find the inverse f(x) = 4x+2

alexdok [17]

Answer:

Let's solve for x.

y=4x+2

Step 1: Flip the equation.

4x+2=y

Step 2: Add -2 to both sides.

4x+2+−2=y+−2

4x=y−2

Step 3: Divide both sides by 4.

4x/4=y−2/4

x=1/4y+ −1/2

Answer:

x=1/4y+ −1/2

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Step-by-step explanation:

4 0

3 years ago

Solve x2=22. Use a radical sign in each answer<br><br> x=? and x=?

Aleksandr-060686 [28]

Answer:

x=sqrt{22}

Step-by-step explanation:

4 0

3 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

<em>P(0) = 0 and P(50) = 1,500,000 </em>

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

so

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

3 years ago

A jar is filled up with buttons of various colors. Of the jar has a total of 875 buttons and 52% of buttons are green, how many

laiz [17]

Since 52% is the same as 52/100, we can multiply 875 by 52/100 in order to find the green buttons.
52/100(875) = 455
455 green marbles

3 0

3 years ago