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Ilya [14]
3 years ago
11

What is the reading in kwhr of the electric meter shown in the exam figure below?

Mathematics
1 answer:
just olya [345]3 years ago
7 0

We can't tell, because you won't let us SEE
the electric meter shown in the exam figure.

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Simplify : 5c + 3 – 12c – 8
Shtirlitz [24]

Answer:

Step-by-step explanation:

-7c - 5

8 0
3 years ago
State if the triangle is congruent
melisa1 [442]

Answer:

Step-by-step explanation:

m∠ JHI + m∠GHJ = 180    { linear pair}

m∠JHI + 90 = 180

m∠JHI = 180 -90 = 90

In ΔGHJ and ΔJHI,

          GJ = IJ   { given}

         JH = JH    {common}

 m∠ JHI = m∠GHJ  { above proved}

ΔGHJ  ≅ ΔJHI     { Angle Side Side congruence}

8 0
3 years ago
I will mark as brainliest<br><br> Do 1-9
dangina [55]
To solve this problem, we need to know the formulas for the areas of each of these shapes. The formula for the area of a circle is πr², the area of a rectangle is b * h, the area for a square is s², and the area for a triangle is 0.5bh. Now we can solve.

1) This is a circle, so the area is πr² = π(6)² = 36<span>π square feet

2) This is a square, so the area is s</span>² = 12² = 144 square yards

3) This is a rectangle, so the area is b * h = 6 * 14 = 84 square inches

4) This is a rectangle, so the area is b * h = 7 * 3 = 21 square inches

5) This is a circle, so the area is πr² = π(4)² = 16<span>π square feet

6) This is a triangle, so the area is 0.5bh = 0.5 (8 * 8) = 0.5 * 64 = 32 yd.</span>²

7) This is a triangle, so the area is 0.5bh = 0.5 (5 * 10) = 50 * 0.5 = 25 yd.²

8) This is a rectangle, so the area is b * h = 10 * 2 = 20 in²

9) This is a square, so the area is s² = 9² = 81 ft²
5 0
4 years ago
5x + 9 = x - 23 find X​
Doss [256]

5x + 9 = x - 23

move x to the other side

sign changes from +x to -x

5x-x+9= x-x-23 ( combine like terms)

5x-x+9= -23

4x+9= -23

move -9 to the other side

4x+9-9= -23-9

4x= -23-9

4x= -32

divide both sides by 4 to get x by itself

4x/4= -32/4

answer:

x= -8

7 0
3 years ago
. Write the equation for a circle with center (0, −4) and radius 8.
balu736 [363]
<h2>Equation for a circle with center (0, −4) and radius 8 is x²+y²+8y-48 = 0</h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

          (x-h)²+(y-k)² = r²

Here we need to find equation for a circle with center (0, −4) and radius 8.

Center = (h,k) = (0, −4)

Radius = r = 8

Substituting in equation

              (x-h)²+(y-k)² = r²

               (x-0)²+(y-(-4))² = 8²

               x²+(y+4)² = 64

                x²+y²+8y+16 = 64

                x²+y²+8y-48 = 0

Equation for a circle with center (0, −4) and radius 8 is x²+y²+8y-48 = 0

8 0
3 years ago
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