All categories

3 years ago

C. Polynomial functions: y = x4 - 3x2 - 3Leading termLeading coefficient :Degree:

Mathematics

1 answer:

MrRissso [65]3 years ago

3 0

Answer:

Step-by-step explanation:

hello : here is an solution

Leading coefficient : 1 , 0 , -3 ,0 , -3 because : y = 1x4+0x^3 - 3x2+0x - 3

Degree: 4

You might be interested in

one section of wood is 3 5/8 meters long. another section is twice that long. when the two pieces are put together how many is t

madreJ [45]

Answer:

the mixed number form is 10 7/8

8 0

2 years ago

Christy solved this problem. A store charged a customer $445.50 for 150 floor tiles . What is the price of each tile? Christy th

Ivan

A is correct because 445.50 Divided By 150 is Equal to $2.97.

5 0

3 years ago

Read 2 more answers

Sally has 4 apples and maria has 9. How many apple to they have in total

krek1111 [17]

Answer:

Step-by-step explanation:

4 + 9

[ 9 + 2 = 11 ]

[ 11 + 2 = 13 ]

8 0

2 years ago

Read 2 more answers

Can someone please explain this to me? Thanks!

Makovka662 [10]

Answer: Choice D

$\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\$

==========================================================

Explanation:

Let g(t) be the antiderivative of $g'(t) = \sqrt{1+t^3}$ . We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

$\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)$

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

$\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\$

From here, we apply the derivative with respect to x to both sides. Note that the $g(\pi)$ portion is a constant, so $g'(\pi) = 0$

$\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\$

$\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\$

Answer is choice D

5 0

2 years ago

Read 2 more answers

Someone factor x^2+18x+77

Ipatiy [6.2K]

77 is a multiple of 11, as i'm sure you know--the double numbers like 22 and 55, one of the factors are always 11.

77 is factored down into 11 and 7--which, when you add those, luckily equal 18.

(x + 11)(x + 7) is your factorization.

5 0

4 years ago

C. Polynomial functions: y = x4 - 3x2 - 3Leading termLeading coefficient :Degree:​

C. Polynomial functions: y = x4 - 3x2 - 3Leading termLeading coefficient :Degree: