Answer:
Stephen's neighbors paid Stephen no more that $28.
Step-by-step explanation:
Given:
Stephen spent $5 of his earnings on snack.
He spent $17 in a new book.
He is left with no more than $6 left.
To describe how much Stephen's neighbors paid him.
Solution:
Let Stephen's earnings in dollars be = 
Amount left after spending on snacks in dollars = 
Amount left after spending on a new book in dollars = 
= 
The amount remaining is no more than $6.
Thus, the inequality representing the situation can be given as:
Solving for
Adding 22 both sides.
Thus, Stephen's neighbors paid Stephen no more that $28.
The inverse function is equal to f-1(x) = (x - 1)/3 and the value at f-1(6) is equal to 5/3.
To find the inverse, you need to switch the f(x) and x in the equation. Then you can solve for the new f(x). The result will be the inverse (f-1)
f(x) = 3x + 1 ----> Switch f(x) and x
x = 3f(x) + 1 ----> Subtract 1
x - 1 = 3f(x) ----> Divide by 3.
f-1(x) = (x - 1)/3
Now that we have the inverse, we can plug 6 in to get the value at f-1(6).
f-1(x) = (x - 1)/3
f-1(6) = (6 - 1)/3
f-1(6) = 5/3
Answer:
Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200
Step-by-step explanation:
p = 400 - 4x
4x = 400 - p
x = (400 - p) / 4 → x = 100 - p/4
Elasticity of demand [ P ed ] = (Δx / Δp) x (p / x)
Δx / Δp [Differentiating x w.r.t p] = 0 - 1/4 → = -1/4
P ed = <u>-1</u> x<u> p </u>
4 (400 - p)/4
= <u>-1</u> x <u> 4p </u> = -p / (400-p)
4 (400 - p)
Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).
So, Ped = p / (400 - p)
Demand is Elastic when P.ed > 1
p / (400-p) > 1
p > 400 - p
p + p > 400 → 2p > 400
p > 400 / 2 → p > 200
Demand is inelastic when P.ed < 1
p / (400-p) < 1
p < 400 - p
p + p < 400 → 2p < 400
p < 400 / 2 → p < 200
You should have received 33 pairs of protective eyewear
To Check This:
1 dozen = 12
1/2 dozen = 6
5 dozen = 60
12x5=60+6=66
66 / 2 = 33 because a pair equals 2
Answer: 4x10^2
Step-by-step explanation:
