Answer: 1.07×10^-20microlitre
Explanation:
1cm3 = 1000microlitres
1.07×10^-23 cm3 of tungsten = 1.07×10^-23 x 1000 = 1.07×10^-20microlitre
Answer:
Before we go through this I ask you carefully read every thing I've listed out or it's not going to make sense for you.
The equation:
CO2 and O2 aren't reacting with each other. One is a product and the other is a reactant. You're probably asking for how much CO2 will be formed with 17 moles of O2. It's pretty simple.
First you have to find the mole to mole ratio of O2 to CO2 (look at their coefficients/numbers right in front of their names), the ratio is 9 : 6, so for every 9 of oxygen gas (O2), 6 of carbon dioxide (CO2) is made. We have 17 moles of oxygen so if we divide it by 9 (mole ratio of oxygen gas) and multiply it by 6, we will get the amount of CO2 produced.
<u>(17/9) x 6 ≈ 11.3 moles of CO2 are made. </u>
In the case that you actually meant to say C3H7OH (Propanol) reacting with oxygen, I'll write that down here too:
The mole to mole ratio of Propanol to Oxygen gas is 2 : 9 (look at the coefficients) so we divide 17 moles of oxygen by 9 and then multiply it by 2, which will give us the amount of Propanol needed.
<u>(17/9) x 2 = 3.78 moles of Propanol is required to react with oxygen.</u>
Answer:
1) Increasing the pressure A) Shift to the left
2) Removing hydrogen gas B) Shift to the right
3) Adding a catalyst C) No effect
Explanation:
- <em>Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
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<u><em>1) Decreasing the pressure:</em></u>
- When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 4.0 moles of gases and the products side (right) has 2.0 moles of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).
<u><em>so, the right match is: A) Shift to the left.</em></u>
<em><u>2) Adding hydrogen gas:</u></em>
- Adding hydrogen gas will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the increase in the concentration of hydrogen gas by addition.
<u><em>so, the right match is: B) Shift to the right.</em></u>
<u><em></em></u>
<u><em>3) Adding a catalyst:</em></u>
- Catalyst increases the rate of the reaction without affecting the equilibrium position.
- Catalyst increases the rate via lowering the activation energy of the reaction.
- This can occur via passing the reaction in alternative pathway (changing the mechanism).
- The activation energy is the difference in potential energies between the reactants and transition state (for the forward reaction) and it is the difference in potential energies between the products and transition state (for the reverse reaction).
- in the presence of a catalyst, the activation energy is lowered by lowering the energy of the transition state, which is the rate-determining step, catalysts reduce the required energy of activation to allow a reaction to proceed and, in the case of a reversible reaction, reach equilibrium more rapidly.
- with adding a catalyst, both the forward and reverse reaction rates will speed up equally, which allowing the system to reach equilibrium faster.
<u><em>so, the right match is: B) No effect.</em></u>
<u><em></em></u>
Answer: The coefficient for water after the equation is balanced is 2.
Explanation:
The balanced chemical equation must have same charge and same number of atoms on both sides of the equation.
As the given reaction is a redox recation occuring in acidic medium.
The coefficient for water will be 2 after the equation is balanced.