<img src="https://tex.z-dn.net/?f=%5Cbf%203x%2B9%3D-18" id="TexFormula1" title="\bf 3x+9=-18" alt="\bf 3x+9=-18" align="absmiddl

Ask question

Ask question

All categories

2 years ago

10

e" class="latex-formula">

2 answers:

ludmilkaskok [199]2 years ago

8 0

Answer:

x= -9

Step-by-step explanation:

Subtract 9 from both sides:

3x+9−9=−18−9

Simplify:

3x=−27

Divide both sides by 3

(3x/3) =(−27/3)

Simplify again to get the result!

x= -9

Studentka2010 [4]2 years ago

6 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

value of x is ~

$\boxed{ - 9}$

Here's the solution teeny ~

$3x + 9 = - 18$

$3x = - 18 - 9$
$3x = - 27$

$x = - 27 \div 3$

$x = - 9$

Hope it helps ~

You might be interested in

12 spheres of the same size are made from melting a solid cylinder of 1 cm diameter and 2 cm height. Find the diameter of each s

mars1129 [50]

The answer is: The diameter is 4 centimeters.

The explanation is shown below:

1. The volume of the cylinder is:

$Vc=r^{2}h \pi$

Where $r$ is the radius ( $r=\frac{16cm}{2}=8cm$ ) and $h$ is the height ( $h=2cm$ ).

Then:

$Vc=(8cm)^{2}}(2cm)\pi\\Vc=128\pi$

2. The total volume of the 12 spheres is:

$Vs=12(\frac{4}{3}r^{3}\pi)\\Vs=16r^{3}\pi$

3. The volume of the cylinder and the total volume of all the 12 spheres, are equal, therefore:

$Vc=Vs\\128\pi=16r^{3}\pi$

4. Now, you must solve for the radius:

$r=\sqrt[3]{\frac{128\pi}{16\pi}}\\r=2cm$

5. The diameter is:

$d=2r\\d=2(2cm)\\d=4cm$

5 0

3 years ago

Which equation represents a parabola that opens upward, has a minimum at x = 3, and has a line of symmetry at x = 3?

densk [106]

Answer:

$A.\ y = x^2 - 6x + 13$ is the correct answer.

Step-by-step explanation:

We know that vertex equation of a parabola is given as:

$y = a(x-h)^2+k$

where $(h,k)$ is the vertex of the parabola and

$(x,y)$ are the coordinate of points on parabola.

As per the question statement:

The parabola opens upwards that means coefficient of $x^{2}$ is positive.

Let $a = +1$

Minimum of parabola is at x = 3.

The vertex is at the minimum point of a parabola that opens upwards.

$\therefore$ $h = 3$

Putting value of a and h in the equation:

$y = 1(x-3)^2+k\\\Rightarrow y = (x-3)^2+k\\\Rightarrow y = x^2-6x+9+k$

Formula used: $(a-b)^2=a^{2} +b^{2} -2\times a \times b$

Comparing the equation formulated above with the options given we can observe that the equation formulated above is most similar to option A.

Comparing $y = x^2 - 6x + 13$ and $y = x^2-6x+9+k$

13 = 9+k

k = 4

Please refer to the graph attached.

Hence, correct option is $A.\ y = x^2 - 6x + 13$

3 0

3 years ago

Read 2 more answers

four friends buy tickets for two shows on consecutive nights. They use a coupon for $5 off each ticket. They pay a total of $416

Serjik [45]

do u want the answer or how to solve it?

6 0

3 years ago

Read 2 more answers

What is the domain of the sine and cosine functions?

eimsori [14]

Answer:

domain of the sine and cosine functions is all real numbers

Step-by-step explanation:

range of both the sine and cosine functions is [−1,1]

graph can go left and right to infinity

graph goes up and down between 1 and -1

graph looks like a wave or

like U letters next to each other

UUUU

sine and cosine of an angle have the same absolute value as the sine and cosine of its reference angle.

mathlibretextsorg

8 0

1 year ago

Whats an equation in the form of y=ax+b ?

Step2247 [10]

Answer: Slope-Intercept

6 0

2 years ago