<img src="https://tex.z-dn.net/?f=%5Cbf%203x%2B9%3D-18" id="TexFormula1" title="\bf 3x+9=-18" alt="\bf 3x+9=-18" align="absmiddl

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Airida [17]

2 years ago

e" class="latex-formula">

Mathematics

2 answers:

ludmilkaskok [199]2 years ago

8 0

Answer:

x= -9

Step-by-step explanation:

Subtract 9 from both sides:

3x+9−9=−18−9

Simplify:

3x=−27

Divide both sides by 3

(3x/3) =(−27/3)

Simplify again to get the result!

x= -9

Studentka2010 [4]2 years ago

6 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

value of x is ~

$\boxed{ - 9}$

Here's the solution teeny ~

$3x + 9 = - 18$

$3x = - 18 - 9$
$3x = - 27$

$x = - 27 \div 3$

$x = - 9$

Hope it helps ~

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A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and

Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

$Hypotenuse^2=Base^2+Perpendicular^2$

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

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$0=2x^2+10x-72.0225$

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Approximating the value, we get

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$x=\dfrac{16}{4},\dfrac{-36}{4}$

$x=4,-9$

Distance cannot be negative so $x\neq -9.$

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$x+5=4+5$

$x+5=9$

Therefore, the base is 4 m and the height is 9 m.

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