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soldi70 [24.7K]
3 years ago
12

Can you help me with this work please?

Mathematics
1 answer:
svp [43]3 years ago
3 0

9514 1404 393

Answer:

  OL = 7

Step-by-step explanation:

Triangle JKL is isosceles and N is the midpoint of JL, so NL = NJ = 14.

Triangle LMN is isosceles and O is the midpoint of NL, so NL = 2(OL).

  OL = NL/2 = 14/2

  OL = 7

__

There is no WY.

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Pls help me in these questions
Maru [420]

1.n>7

2. is 55

3. is 6

7 0
3 years ago
George needs to rent a car for one day. He can rent a Cadillac from Gamma Car Rental for $30.39 per day plus 55 cents per mile.
oksian1 [2.3K]
Call the number of days 'd' and the number of miles 'm'.
(Original, eh ?)

Then the equation for Gamma's price is

                           Price-G = 30.39d + 0.55m

and the equation for Delta's price is

                            Price-D = 50.31d + 0.43m .

We're going to set the prices equal, and find out
what the number of miles is:

                       Price-G = Price-D.

        30.39d + 0.55m  = 50.31d + 0.43m .

Before we go any farther, I'm going to assume that both cases would be
one-day rentals.  My reasons:  ==> the solution for the number of miles
depends on how many days each car was rented for;  ==> even if both
cars are rented for the same number of days, the solution for the number
of miles depends on what that number of days is.

For 1-day rentals, d=1, and

                                        30.39 + 0.55m  =  50.31 + 0.43m .
Beautiful.  Here we go.
Subtract 0.43m
from each side:              30.39 + 0.12m  =  50.31

Subtract 30.39
from each side:                            0.12m  =  19.92

Divide each side by 0.12 :                  m  =  166 .

There it is !  If a car is rented from Gamma for a day, and another car
is rented from Delta for a day, and both cars are driven 166 miles, then
the rental prices for both cars will be the same ... (namely $121.69)
4 0
3 years ago
Got 2 vector questions here which I would be very grateful if you could help me solve it
Lubov Fominskaja [6]

Step-by-step explanation:

1st question

a)AB=-a+b=b-a

b)OC=a+b-a+3/2(b-a)=b+3/2b-3/2a=5/2b-3/2a=(5b-3a)/2

2nd question

a)CA=2a

b)AB=-a+b=b-a

c)BC=-b-a

7 0
3 years ago
An (independent or dependent) variable can be assigned any value. The variable that changes depending on the (independent or dep
True [87]

Answer:

  • An <em>independent</em> variable can be assigned any value. The variable that changes depending on the <em>independent</em> variable is called the <em>dependent</em> variable.
  • If x is the independent variable, then <em>y</em> would be considered the dependent variable and will change depending on the value of <em>x</em>.

Step-by-step explanation:

The key word is "depending". The <em>dependent</em> variable changes depending on the <em>independent</em> variable.

3 0
4 years ago
Evaluate 8 + 3e when e = 2.<br> Need the Answer
alexandr402 [8]

Answer:

The answer is 14

Step-by-step explanation:

e=2

Substitute 2 in for e

8 + 3(2)

Solve

14

6 0
3 years ago
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