Answer:
If there are 1000 customers in the store one week, how many will purchase exactly one of these items
1000 CUSTOMERS*28%=280
Step-by-step explanation:
A The event that a persons buys a suit
B The event that a person buys a shirt
C The event that a person buys a tie
P(A)= 22%
P(B)= 30%
P(C)= 28%
P(AB)=
11%
P(AC)=
14%
P(BC)=
10%
P(ABC)=
6%
A u B u C Is the event that any item is bougth
AC u AC u BC Is the event that any two events occured
So the wanted probability is
P[(A u B u C )(AB u AC u BC)^c
P[(A u B u C )=P(AB)+ P(BC)+P(BC)
P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06
=0,51
0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c
=0,28
1000 CUSTOMERS*28%=280
Diagram please
Without diagram I cannot tell you the answer
Answer:
Step-by-step explanation:
5 bags= $12.50
1= ?
$12.50*1= 12.50
$12.50/5= $2.5
$2.5*5=$12.5
$2.5*3= $7.5
3 bags= $7.5
Answer: I subtracted 8 from both sides then divided 3 on both sides
Step-by-step explanation: welcome
