Answer:
Bus speed: 22 mph; Trolley speed: 14 mph
Step-by-step explanation:
Let rb represent the speed of the bus and rt the speed of the trolley. Then rb = rt + 8 (mph).
Recall that distance = rate times time. Two different distances and two different speeds are involved here, but only one time.
Thus,
60 mi 44 mi
--------------------- = time (same in both cases) = -------------
rt + 8 mi/hr rt
Cross-multiplying, we get 44rt + 8(44) = 60 rt, or
352 = 16rt.
Solving this for rt, we get rt = speed of bus = 352/16 = 22 mph
The speed at which the bus travels is 22 mph and that at which the trolley travels is (22 mph - 8 mph) = 14 mph
5x + 7 = 27
5x = 27 - 7
5x = 20
x = 20 ÷ 5
x = 4
2p - 15 = 35
2p = 35 + 15
2p = 50
p = 50/2
p = 25
Answer:
To solve the equation, you have to to isolate the variable. So, first you subtract both sides by 7.
x +7 - 7 = -2 - 7
When you simplify further,
x = -9.
Hope this helps! :)
Answer:
-4+10 AND 8-2
Step-by-step explanation: