Answer:
a) v = 88.54 m/s
b) vf = 26.4 m/s
Explanation:
Given that;
m = 1400.0 kg
a)
by using the energy conservation
loss in potential energy is equal to gain in kinetic energy
mg × ( 3200-2800) = 1/2 ×m×v²
so
1400 × 9.8 × 400 = 0.5 × 1400 × v²
5488000 = 700v²
v² = 5488000 / 700
v² = 7840
v = √7840
v = 88.54 m/s
b)
Work done by all forces is equal to change in KE
W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)
we substitute
1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf² -0 )
488000 = 700 vf²
vf² = 488000 / 700
vf² = 697.1428
vf = √697.1428
vf = 26.4 m/s
Answer:
Answer:B
Explanation:
Because it all stayed consistant
Answer:
Yes
Explanation:
In a third-class lever, the effort force lies between the resistance force and the fulcrum. Some kinds of garden tools are examples of third-class levers. When you use a shovel, for example, you hold one end steady to act as the fulcrum, and you use your other hand to pull up on a load of dirt.
Answer:In a DC circuit, the power consumed is simply the product of the DC voltage times the DC current, given in watts.for AC circuits with reactive components we have to calculate the consumed power differently.
a 1/4 watt resistor or a 20 watt amplifier.
Explanation:
1. Acceleration is the change in velocity over time.
a = Δv / Δt
a = (29.8 m/s − 37.1 m/s) / 3 s
a = -2.43 m/s²
2. Work equals force times distance.
W = Fd
W = (87.3 N) (2.04 m)
W = 178 J
3. Power is work per time.
P = W / t
267 W = 1250 J / t
t = 4.68 s
