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navik [9.2K]
3 years ago
14

How can i work this problem out

Mathematics
1 answer:
muminat3 years ago
3 0

The form of the linne is given by
Y=mx +b
Where b is the y intercept of the line
That is the point where the line cuts the y axis
So here b= -3
So
Equation is
Y=1/3 x +(-3)
Answer in place of question mark is -3

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7 0
3 years ago
What is the answer to this question ? Please answer !!
mylen [45]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ k:y=m_2x+b_2,\ \text{then}\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\-------------------------\\\text{We have}\ 5x-y=-4.\ \text{Convert it to the slope-intercept form:}\\\\5x-y=-4\qquad\text{subtract 5x from both sides}\\\\-y=-5x-4\qquad\text{change the signs}\\\\y=5x+4\to m_1=5\to m_2=-\dfrac{1}{5}\\\\\text{Therefore we have}\ y=-\dfrac{1}{5}x+b.\\\\\text{The line passing through the point (-2, 2).}\\\text{Put the coordinates of the point to the equation:}

2=-\dfrac{1}{5}(-2)+b\\\\2=\dfrac{2}{5}+b\qquad\text{subtract}\ \dfrac{2}{5}\ \text{from both sides}\\\\1\dfrac{3}{5}=b\to b=\dfrac{8}{5}\\\\\text{Therefore we have the equation of a line in slope-intercept form:}\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\\\\\text{Convert it to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\qquad\text{multiply both sides by 5}\\\\5y=-x+8\qquad\text{add x to both sides}\\\\\boxed{x+5y=8}\to\boxed{[B]}

8 0
3 years ago
Which of the following could Not be the side length of a right triangle?
ArbitrLikvidat [17]

Answer:

I think ITS B

Step-by-step explanation:

Hope this helped

-BB

8 0
3 years ago
Read 2 more answers
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