Given :
Center of sphere , C( 1 , -1 , 6 ) .
To Find :
Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .
Solution :
a)
Distance of the point from xy-plane is :
d = 6 units .
So , equation of circle with center C and radius 6 units is :
b)
Distance of point from yz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
c)
Distance of point from xz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
Hence , this is the required solution .
Answer:
x= 16
Step-by-step explanation:
8x + 50 = 178
8x = 178- 50
8x = 128
x = 128/8
x = 16
I think its A. There is a peak in the orders from 6 to 10 pounds
The expression that can be used to approximate the expression below is
- Given the logarithmic function expressed as
, we need the log expression that is equivalent to the given expression.
- To do this, we will write the logarithm as a quotient to the same base. Using the base of 10, the expression can be written as;
This is similar to the option c where the base of "b" was used as
Learn more on law of logarithms here: brainly.com/question/11587706
