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nalin [4]
3 years ago
6

In the problem 19.28 - 1.546, first round each number to the nearest tenth. Then subtract.​

Mathematics
1 answer:
goblinko [34]3 years ago
8 0

Answer:

17.8

Step-by-step explanation:

First, round the two. umbers to the nearest the th, or the first number past the decimal.  19.28 rounds to 19.3 (round up because 8 is bigger than 5) and 1.546 rounds to 1.5 (round down because 4 is smaller than 5).  Then subtract.  19.3 - 1.5 = 17.8

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FinnZ [79.3K]
68 Divided by 5 is 13.6
5 0
3 years ago
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On a certain hot summers day, 648 people use the public swimming pool. The daily prices are $1.50 for children and $2.25 for adu
ehidna [41]

Answer:

252 children and 395 adults

Step-by-step explanation:

Make a linear system of equations, where x represents the number of children and y represents the number of adults

x+y=648

1.50x+2.25y=1269

solve using substitution, so y=648-x,

then substitute this into the second equation, so you get 1.50x+2.25(648-x)=1269,

solve for x and you will get x equals the 252

then substitute this into the first equation, so you get 252+y=648

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3 0
3 years ago
A townhouse in San Francisco was purchased for $80,000 in 1975. The appreciation of the building is modeled by the equation: A=8
jonny [76]

Answer:

In 1981 was the building worth double it’s value.

Step-by-step explanation:

Given : A townhouse in San Francisco was purchased for $80,000 in 1975. The appreciation of the building is modeled by the equation : A=80000(1.12)^t, where t represents time in years.

To find : In what year was the building worth double it’s value in 1975?

Solution :

The amount is $80,000.

The building worth double it’s value in 1975.

i.e. amount became A=2(80000).

Substitute in the model,

2(80000)=80000(1.12)^t

(1.12)^t=\frac{2(80000)}{80000}

(1.12)^t=2

Taking log both side,

t\log (1.12)=\log 2

t=\frac{\log 2}{\log (1.12)}

t=6.11

i.e. Approx in 6 years.

So, 1975+6=1981

Therefore, in 1981 was the building worth double it’s value.

4 0
4 years ago
A family tree business removes overgrown trees for 3 months in the summer. In June, they removed 1/3 the number of trees as they
devlian [24]

Answer: 299

Step-by-step explanation:

Given

Family removes one-third of tress in June as much as they dd in July

They remove twice the number of July in august

Suppose they removed x trees in July

for June it is, \frac{x}{3}

for August, it is 2x

If they removed less than 1000 tress in 3 months

\Rightarrow \dfrac{x}{3}+x+2x

So, maximum number of tress removed in July is 299

7 0
3 years ago
What does 3/5 equal to as a decimal
sergiy2304 [10]
\frac{3}{5}=\frac{3\times2}{5\times2}=\frac{6}{10}=0.6\\\\other\ method:\\\\\underline{0.6}\\3:5\\\underline{0}\\30\\\underline{30}\\R=0\\\\\frac{3}{5}=0.6

5 0
4 years ago
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