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nalin [4]
2 years ago
6

In the problem 19.28 - 1.546, first round each number to the nearest tenth. Then subtract.​

Mathematics
1 answer:
goblinko [34]2 years ago
8 0

Answer:

17.8

Step-by-step explanation:

First, round the two. umbers to the nearest the th, or the first number past the decimal.  19.28 rounds to 19.3 (round up because 8 is bigger than 5) and 1.546 rounds to 1.5 (round down because 4 is smaller than 5).  Then subtract.  19.3 - 1.5 = 17.8

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ohaa [14]

Answer: Hello!

In this problem you can chose 3 options:

the type of cone, the first flavour, and the second flavour.

a) In how many different ways can your order one cone and two scoops of ice cream?

You have 5 options for cones, 9 options for the first ball of ice cream, and 9 options for the second ball of ice cream (because you can repeat flavour) then the total number of combinations is the product of this 3 numbers, this is:

5*9*9 = 405 combinations

b) Here we cant order the same flavour of ice cream, then:

we still have 5 options for cones, 9 options for the first ball of ice cream, and this time 8 options for the second ball ( because we need to remove the flavour that we picked in the first ball of ice cream) then the number of combinations is:

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6 0
3 years ago
S=a+(n-1)d,solve for d​
Vinvika [58]

Answer:\frac{s-a}{n-1}

Step-by-step explanation:

formula, s=a+(n-1)d

1. get rid of the a on d's side by subtracting it from both sides.  

s=a+(n-1)d   becomes s-a=(n-1)d

2. get rid of (n-1) by dividing it from both sides. s-a=(n-1)d   becomes  

\frac{s-a}{n-1} =d  

5 0
3 years ago
four sisters bought a present for their grandfather that cost each sister $8. they recieved a 20% discount how much was the orig
Westkost [7]
8x4=$32
80%-$32
100%= 32/80 x 100 = $40
4 0
3 years ago
Which expression is equivalent to b^m•b^n<br> A. b^m-n<br> B. b^m•n<br> C. b^m÷n<br> D. b^m+n
Step2247 [10]
   
\displaystyle\\ &#10;\bold{b^m \times b^n = b^{m + n}~~~(D)}\\\\ &#10;\bold{\frac{b^m}{b^n}= b^{m - n}~~~~~~~~~(A)}\\\\ &#10;\bold{\Big(b^m \Big)^n = b^{m\times n}~~~~(B)}\\\\ &#10;\bold{\sqrt[\bold{n}]{\bold{b^m}} = b^{m\div n } ~~~~~~(C)}



6 0
2 years ago
Help? Please?<br><br> Round the number to the thousandths place "79337.945573"
Ivan

\approx79337.946

7 0
3 years ago
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