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ivanzaharov [21]
2 years ago
14

A = 1/3 find the value of expression 6a + 4​

Mathematics
1 answer:
allochka39001 [22]2 years ago
5 0

Answer:

6

Step-by-step explanation:

1/3 times 6 = 2

2 +  6 = 6

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E-4 - 5 - 6 - → The perimeter of a rectangle is 425 yards. The length and width of the rectangle are each multiplied by 6. What
Alex73 [517]

Answer:

2550yards

Step-by-step explanation:

Perimeter of a rectangle = 2L + 2W

L is the length

W is the width

If perimeter of a rectangle is 425 yards, then;

425 = 2L + 2W

425 = 2(L+W)

L+W = 425/2 .... 1

If the length and width of the rectangle are each multiplied by 6

P = 6(2L) + 2(2W)

P = 12L + 12W

P = 12(L+W) .... 2

Substitute 1 into 2

P = 12(425/2)

P = 6*425

P = 2550yd

Hence the perimeter of new triangle is 2550yards

4 0
2 years ago
Read 2 more answers
Whats 2+2 i dont know what it is
SOVA2 [1]

Answer:

4

Step-by-step explanation:

2+2=4

thanks:D

5 0
3 years ago
Read 2 more answers
Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
Explain in sentences how you can add or subtract two fractions with common denominators?
Lemur [1.5K]
If two fractions have the same denominators, then just simply add up the numerators together and keep the denominator.

Examples:

\frac{4}{10} +  \frac{5}{10} =  \frac{9}{10}

\frac{10}{12} - \frac{2}{12} = \frac{8}{12}
8 0
2 years ago
Graph for f(x)=6^6 and f(x)=14^x
zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0
2 years ago
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