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gogolik [260]
3 years ago
10

Relationships in Figures

Mathematics
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

C. 9.87

Step-by-step explanation:

I calculated it logically

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A process produces batches of a chemical whose impurity concentrations follow a normal distribution with a variance of175. A ran
Tom [10]

Answer:

the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

Step-by-step explanation:

since the variance  S² of the batch follows a normal distribution , then for a sample n of  20 distributions , then the random variable Z:

Z= S²*(n-1)/σ²

follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom

since

S² > 3.10 , σ²= 1.75 , n= 20

thus

Z > 33.65

then from χ² distribution tables:

P(Z > 33.65) = 0.02020

therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

8 0
3 years ago
Read 2 more answers
Each morning Rin rides 1.5 miles to school and then rides home in the afternoon. Later in the evening, she rides to the park and
brilliants [131]

Answer:

Last equation given in the list of possible answers:

5 ( 1.5 + 1.5 + x ) = 25

Step-by-step explanation:

We need to include in the total addition of miles ridden during the week:

a) 1.5 miles to the school

b) 1.5 miles from school back home

c) x miles for the evening ride

so for the miles ridden per day we have: "1.5 +1.5 + x"

Now, since per week she does 5 days like this, then we need to multiply the expression above by 5 in order to total the number of miles she rides weekly (25 miles)

5 ( 1.5 + 1.5 + x ) = 25

And we can use this equation to find the amount "x" that Rin rides in the evening.

7 0
3 years ago
Find the length of the segment with endpoints of (3,2) and (-3,-6).
MakcuM [25]
The formula of the length of the segment AB:
A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}
We have:
A(3;\ 2)\to x_A=3;\ y_A=2\\\\B(-3;\ -6)\to x_B=-3;\ y_B=-6
Substitute:
|AB|=\sqrt{(-3-3)^2+(-6-2)^2}=\sqrt{(-6)^2+(-8)^2}\\\\=\sqrt{36+64}=\sqrt{100}=10
Answer: B) 10.

5 0
3 years ago
Help needed!!! Serious answers only
timurjin [86]

B is the answer I think but so t take my word for it

7 0
3 years ago
The rule below shows how to find the position of an object thrown upward with initial velocity of 15 feet per second. Which answ
nekit [7.7K]

Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.


This rule has the form


h(t) = h + v t + (1/2)a*t^2

o o


To adapt this rule to this particular question replace h with 0, as the

o

upward path of the object begins at 0 ft. Replace v with +15 ft/sec.

o


Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.


Then we have the following, with the label F(t):


F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or


F(t) = 15t - 16.1t^2. Thus, Choice D is correct.


Please note: To avoid confusion, please use " ^ " to denote exponentiation:


F(t) = -16t^2 + 15t

5 0
3 years ago
Read 2 more answers
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