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gogolik [260]
3 years ago
10

Relationships in Figures

Mathematics
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

C. 9.87

Step-by-step explanation:

I calculated it logically

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Number 2 please thanks
Alex

Answer:

c) 2x+1

Step-by-step explanation:

Let's x be number of Nick's goals.

Emma has scored 1 more than twice the number of Nicks.

1 more is +1, of twices the number is 2x.

so 2x+1=15

6 0
3 years ago
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Please answer these questions on circumference for BRAINLIEST and extra points if correct! Show you work please
Pavel [41]

I attached the document with the answers and work with the formulas. Since the formulas and fractions don't work very well with this site (especially the pi symbol, they should fix that).

:)

Download docx
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> docx </span>
1c89019158635bcffd1d757e39c866af.jpg
85756c248c5e0f41e578f4bc19e55e5d.jpg
4 0
3 years ago
Please help it’s due today at 6:10am please help me please please need help please
zepelin [54]

Answer:

Step-by-step explanation:

a. 3-4x=-7-4x

3=-7. no solution

b. 15 - 2x = -7x

15 = -5x

x=-3. one solution

c. 7y-21=6y-21

y=0

1. -3x+4=-3x+7

4=7

2. 10+2x = 5x+2

8=3x

x=3/8

3. x+5=x+5

8 0
3 years ago
Read 2 more answers
A
11Alexandr11 [23.1K]

Answer:

4cm

Step-by-step explanation:

Volume of a prism :Area of cross section x height.

so,

72cm^3 = 18cm^2 x h

h = 72/18 = 4cm

Hope this helps

Good Luck

6 0
3 years ago
if h=-16t ²+160t represents the height of a rocket in T seconds after it was fired when will the rocket hit the ground?
makkiz [27]

Answer:

The time after which the rocket hit the ground is 5 seconds

Step-by-step explanation:

Given as :

The distance of the cover by rocket at the height h = - 16 t² + 160 t

Let the time after which rocket hit the ground = T seconds

Now, When the rocket hits the ground, then at that time, the velocity of the rocket becomes zero.

I.e velocity = \frac{\partial h}{\partial t} = 0

Or, v = \frac{\partial h}{\partial t} = 0

Now, v = \frac{\partial h}{\partial t}

Or, v = \frac{\partial (-16t^{2}+160t)}{\partial t}

or, v = - 32 t + 160

Now, ∵ velocity of rocket after reaching the ground becomes zero

So, v = - 32 t + 160 = 0

Or, 32 t = 160

Or, t = \frac{160}{32}

∴ t = 5 sec

So, The time after which the rocket hit the ground = 5 sec

Hence The time after which the rocket hit the ground is 5 seconds answer

6 0
3 years ago
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