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Sav [38]
3 years ago
11

Simplify 2 √3 times 3 √15 Also simplify 3 √5 times √5 Please help

Mathematics
1 answer:
stira [4]3 years ago
6 0

answer one would be 18 square root of 5

and the second would be 4 square root of 5

Step-by-step explanation:

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Meg has a can that contains 80% of orange juice and the rest water. The can has 1 liter of water.
sammy [17]
<span>x is the total number of liters of orange juice and water combined. 80% of the mixture is pure orange juice which means 20% of it is water. Therefore, x 20/100 = 1 is the equation in single variable that can be used to find x. and 20/100 is 1/5 so there are 5 total liters in all and 5-1 is 4, so there are 4 liters of orange juice in the can. Hope this helps :)</span>
4 0
2 years ago
A group of friends count the coins they have in their pockets.
Len [333]

Answer:

The median stays the same, whilst the mean drops.

Step-by-step explanation:

4 0
2 years ago
Your manufacturing company sells metal nuts and bolts that come together in a package. The diameter of the bolts coming off the
Reil [10]

Answer:

The z score for bolt of diameter 18.12 mm is 1.20.

Step-by-step explanation:

Let <em>X</em> = diameter of bolts.

It is provided that the random variable <em>X</em> follows a Normal distribution with mean, <em>μ</em> = 18 mm and standard deviation, <em>σ</em> = 0.10 mm.

A <em>z</em>-score is a standardized score, a numerical, that defines how far a data value from the mean.

The distribution of <em>z</em>-scores is defined by the Standard Normal distribution.

Z\sim N(0, 1)

The formula to compute the <em>z</em>-score is:

z=\frac{x-\mu}{\sigma}

The value of the diameter of a bolt is, <em>x</em> = 18.12 mm.

Compute the <em>z</em>-score for this value as follows:

z=\frac{x-\mu}{\sigma}=\frac{18.12-18}{0.10}=\frac{0.12}{0.10}=1.20

Thus, the z score for bolt of diameter 18.12 mm is 1.20.

5 0
3 years ago
Two ways to write a algebraic expression of n-5
deff fn [24]
-5 + n is another way to write the expression. 
5 0
3 years ago
Read 2 more answers
In a race in which twelve automobiles are entered and there are no​ ties, in how many ways can the first three finishers come​ i
k0ka [10]
That is 3 slots
12 in 1st slot
11 in 2nd
10 in 3rd

so that is 12*11*10 or 1320 ways
3 0
3 years ago
Read 2 more answers
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