What are three equivalent ratios for 5/45

1 answer:

7 0

$\frac{5}{45}=5:45\ and\ \frac{5}{45}=\frac{5:5}{45:5}=\frac{1}{9}\\\\\frac{5}{45}=\frac{1}{9}\to\boxed{1:9}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot2}{9\cdot2}=\frac{2}{18}=\boxed{2:18}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot3}{9\cdot3}=\frac{3}{27}=\boxed{3:27}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot4}{9\cdot4}=\frac{4}{36}=\boxed{4:36}\\\vdots$

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Find the midsegment of the triangle which is parallel to CA.

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Answer:

$\pmb{ \pink{QUESTION�}}$

Find the midsegment of the triangle which is parallel to CA.

$\pmb{ \pink{ANSWER:-}}$

Tip

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

$\frak{Explanation:-}$

We have to find the segment which is parallel to CA.

From the given data,

The segment EG is the midsegment of the triangle $\triangle$ ABC.

So we have,

A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

$\implies\rm{midsegment \: EG \: parallel \: to \: CA}$

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13. Given the following historical data and weights of .5, .3, and .2, what is the three-period weighted moving average forecast

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Step-by-step explanation:

When calculating the moving average estimate of an observation , each of the observations are usually computed with the same weighted . In some cases, it is beneficial to assign different weight on the observations such that the observation closer to the time period being forecast, has higher weight. This is refer to as weighted moving average technique. The sum of the individual weight in a weighted moving average technique must equal to 1.

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