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2 years ago

What is the probability that time headway is at most 6 sec? (round your answer to three decimal places.)

Physics

1 answer:

FromTheMoon [43]2 years ago

7 0

The probability of that time at which the headway is at most 6 sec is 0.585.

<h3>What is probability?</h3>

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty. The likelihood that an event will occur increases with its probability. A straightforward illustration is tossing a fair (impartial) coin. Since there are no other conceivable outcomes and the coin is fair, the odds of both the possibilities, "heads" and "tails," are equally likely to occur. As a result, the probability of either occurrence is half.

P(X<6) =(1-exp(-0.16*(6-0.5)))

=0.585

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In an aqueous solution where the H+ concentration is 1 x 10-6 M, the OH concentration must be:

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Answer:

D. 1×10⁻⁸ M

Explanation:

[H⁺] [OH⁻] = 10⁻¹⁴

(1×10⁻⁶) [OH⁻] = 10⁻¹⁴

[OH⁻] = 1×10⁻⁸

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3 years ago

A test charge of 13 mC is at a point P where an external electric field is directed to the right and has a magnitude of 4 3 106

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Answer:

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.

Explanation:

From coulomb's law, F = Eq

Thus,

F = E₁q₁

F = E₂q₂

Then

E₂q₂ = E₁q₁

$E_2 = \frac{E_1q_1}{q_2}$

where;

E₂ is the external electric field due to second test charge = ?

E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C

q₁ is the first test charge = 13 mC

q₂ is the second test charge = 23 mC

Substitute in these values in the equation above and calculate E₂.

$E_2 = \frac{4*10^6*13}{23} = 2.26 *10^6 \ N/C$

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.

However, the direction of the external field is still to the right.

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3 years ago

Calculate the displacement of an object at 2.0 seconds when thrown straight up with an

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Answer:

Explanation:

Velocity is the change of rate of displacement with respect to time.

velocity = displacement/time

Given

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time taken =2 secs

Required

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Displacement = Velocity * time

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<em>Hence the displacement of the object is 30m</em>

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3 years ago

A planet orbits a star, in a year of length 3.37 x 107 s, in a nearly circular orbit of radius 1.04 x 1011 m. With respect to th

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Answer

Given,

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a) Angular speed of the planet

$\omega = \dfrac{2\pi}{T}=\dfrac{2\pi}{3.37\times 10^{7}}$

$\omega = 1.864\times 10^{-7}\ rad/s$

b) tangential speed

$v = r \omega = 1.04\times 10^{11}\times 1.864 \times 10^{-7}$

v = 1.94 x 10⁴ m/s

c) centripetal acceleration magnitude

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3 years ago

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Answer:

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