Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
Solving for the midpoint:
x - coordinate: (7.6 + 4.6)/2 = 6.1
y - coordinate: (10.1 + 3.1)/2 = 6.6
Midpoint: (6.1 , 6.6)
Solving for the distance:
Distance formula: sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
D = sqrt( (7.6 - 4.6)^2 + (10.1 - 3.1)^2 <span>)
D = sqrt( 3^2 + 7^2)
D = sqrt(58)
D = 7.62 units
Distance = 7.62 units</span>
Answer:
150
Step-by-step explanation:
Answer:
132
Step-by-step explanation:
13/10+2/100=?/100
Get a common denominator of 100 for the first term
13/10 * (10/10) +2/100=?/100
130/100 + 2/100 = ?/100
132/100 = ? /100
Answer:
102.8
Step-by-step explanation:
If log₁₀y = 2.012, y = 10^2.012 = 102.8
