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MakcuM [25]
3 years ago
10

How many planets on the solar system?

Physics
2 answers:
vitfil [10]3 years ago
4 0

Answer:

8

Explanation:

tsijtsiztuztuistizrizturzurz

Svet_ta [14]3 years ago
3 0

Answer:

8

Explanation:

Mercury, Venus, earth , Mars, jupiter, saturn , Uranus,Neptune

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The gravity on mars is 3.8 m/s2 and you weigh 200 N. your mass will be??
lisabon 2012 [21]

Answer:

Mass = 52.63 kilograms

Explanation:

Given the following data;

Acceleration due to gravity = 3.8 m/s²

Weight = 200 N

To find mass;

Mathematically, the weight of a physical object is given by the formula;

Weight = mass * acceleration due to gravity

Substituting into the formula, we have;

200 = mass * 3.8

Mass = 200/3.8

Mass = 52.63 kg

3 0
3 years ago
40 POINTS CORRECT ANSWER
LUCKY_DIMON [66]
F=-kx
so multiple the two numbers together and put a negative sign in front
 F=-19.25
3 0
4 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
Oksi-84 [34.3K]

Answer:

the equation of motion is

x(t) =-\frac{1}{6} \cos4\sqrt{6} t

Explanation:

Given that,

The weight attached to the spring is 24pounds

Acceleration due to gravity is 32ft/s²

Assume x is the string length, 4inches

convert the length inches to to feet = 4/12 = 1/3feet

From Hookes law , we calculate the spring constant k

k = W / x

k = 24 / (1/3)

k = 24 / 0.33

k = 72lb/ft

If the mass is displace from its equilibrium position by amount x

the differential equation is

m\frac{d^2x}{dt^2} + kx=0\\\\\frac{3}{4 } \frac{d^2x}{dt^2}+72x=0\\

\frac{d^2x}{dt^2} +96x=0

Auxiliary equation is

m^2+96=0\\m=\sqrt{-96} \\m=\_ ^+4\sqrt{6}

Thus the solution is,

x(t) =  c_1cos4\sqrt{6t} +c_2sin\sqrt{6t}

x'(t) =-4\sqrt{6c_1} sin4\sqrt{6t} +c_24\sqrt{6} cos4\sqrt{6t}

The mass is release from rest

x'(0) = 0

-4\sqrt{6c_1 }  \sin4\sqrt{6} (0)+c_24\sqrt{6} \cos4\sqrt{6} (0)=0\\c_24\sqrt{6} =0\\\\c_2=0

Therefore

x(t) = c₁ cos4 √6t

x(0) = -2inches

c₁ cos4 √6(0) = 2/12feet

c₁= 1/6feet

There fore, the equation of motion is

x(t) =-\frac{1}{6} \cos4\sqrt{6} t

7 0
4 years ago
Que actitud Tomárias si te sientes marginado​
tresset_1 [31]
Buscar nuevos amigos, si no te quieren contigo o te ponen de lado, en realidad no son tus amigos o compañeros, nadie se merece eso, no necesitas esas personas en tu vida.
7 0
3 years ago
A 2MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T.the force on a proton is
Snowcat [4.5K]

Answer:

7.8x10-12N

Explanation:

We know that

Magnetic force = F = qVB

And

Also Kinetic energy K.E is

E = (1/2)mV²

So making v subject

V = √(2E / m)

And

E = KE = 2MeV

= 2 × 106 eV

= 2 × 106 × 1.6 × 10–19 J

= 3.2 × 10–13 J

And then

V= √2x3.2E-13/1.6E-27

1.9E7m/s

Given that

mass of proton = 1.6 × 10–27 kg,

Magnetic field strength B = 2.5 T.

So F= qBv sinစ

=

So F = 1.6 × 10–19 × 2.5 × 1.9 x10^7 x sin 90°

= 7.8 x 10^-12N

5 0
3 years ago
Read 2 more answers
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