likely due to the location.
Answer:
The distance is 11 m.
Explanation:
Given that,
Friction coefficient = 0.24
Time = 3.0 s
Initial velocity = 0
We need to calculate the acceleration
Using newton's second law
...(I)
Using formula of friction force
....(II)
Put the value of F in the equation (II) from equation (I)
....(III)

Put the value in the equation (III)


We need to calculate the distance,
Using equation of motion



Hence, The distance is 11 m.
Answer:
h = 18.41 m
Explanation:
Given that,
Mass of a test rocket, m = 11 kg
Its fuel gives it a kinetic energy of 1985 J by the time the rocket engine burns all of the fuel.
According to the law of conservation of energy,
PE = KE = mgh
h is height will the rocket rise

So, the rocket will rise to a height of 18.41 m.
According to the Law of conservation of momentum, the total momentum of the system before and after the collision remains same. The momentum may transfer from one object to another as a result of the impact, but the overall momentum of the system remains same.
So, the correct answer is option a.
The total initial momentum of all objects interacting with one another usually equals the total final momentum.
Answer:
2.0 m
Explanation:
Energy is conserved.
Initial KE = Final PE + Work done by friction
½ mv² = mgh + Fd
½ mv² = mgh + mgμd
½ v² = gh + gμd
½ v² − gh = gμd
d = (½ v² − gh) / (gμ)
d = (½ (7.5 m/s)² − (10 m/s²) (2.1 m)) / ((10 m/s²) (0.35))
d = 2.0 m