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vichka [17]
3 years ago
14

Which two phenomena make up electromagnetism?

Physics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

C and D

Explanation:

The guy above me got it wrong

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3. Which is a type of nitrogenous base? Select all the apply.
Contact [7]

I think the answer is thymine

5 0
3 years ago
Read 2 more answers
A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect a
pochemuha

Answer:

V=14

Explanation:

PE=KE

mgh=1/2mv^2

2(9.8)10=1/2(2)v^2

(radical) 196= (radical)v

V=14

7 0
3 years ago
A rope is attached to a block. The rope pulls on the block with a force of 240 N, at an angle of 40 degrees to the horizontal (t
Tom [10]

Answer:

X Component is 183.85N

Explanation:

The x component of the force on the block due to the rope;

X = F cos @ where if is the force, @ is the angle mad with the block.

X = F cos @

X = 240 cos 40

Cos 40= 0.7660, so

X = 240 × 0.7660

X component= 183.85N// rounded to two decimal places.

3 0
4 years ago
Read 2 more answers
A displacement is related to time as x = A sin(2?ft), where A and f are constants. Find the dimensions of A. [Hint: A trigonomet
Luba_88 [7]

Answer:

The right option is C. i.e L

Explanation:

Dimension of a quantity is the collection of the indexes of each of the fundamental quantities contained in it.

Therefore, to get the dimension of A in the equation

X=Asin(2(pi)ft)

Making A the subject of the formula

A = X / (sin(2(pi)ft)

Since sin(2(pi)ft which is a trigonometric function does not have a dimension

A = L

The dimension of A is L

5 0
3 years ago
A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizo
blondinia [14]

Answer:

His pitching speed is 38 m/s.

Explanation:

Hi there!

Please see the attached figure for a better understanding of the problem.

The position of the ball at any time t is given by the following vector:

r = (x0 + v0 · t, y0 + 1/2 · g · t²)

Where:

r = position vector of the ball at time t.

x0 = initial horizontal position.

v0 = initial horizontal velocity.

t = time.

y0 = initial vertical position.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

Let's place the origin of the frame of reference at the throwing point so that x0  and y0 = 0.

When the ball reaches the ground, its position vector will be r1 (see figure). Using the equation of the vertical component of the position vector, we can find the time at which the ball reaches the ground. At that time, the horizontal component of the position is 30 m and the vertical component is -3.0 m (see figure):

y = y0 + 1/2 · g · t²  (y0 = 0)

y = 1/2 · g · t²

-3.0 m = 1/2 · (-9.8 m/s²) · t²

-3.0 m / -4.9 m/s² = t²

t = 0.78 s

Now, knowing that at this time x = 30 m, we can find v0:

x = x0 + v0 · t  (x0 = 0)

x = v0 · t

30 m = v0 · 0.78 s

v0 = 30 m / 0.78 s

v0 = 38 m/s

His pitching speed is 38 m/s.

3 0
4 years ago
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