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Nata [24]
3 years ago
5

Help me please i will give brainiest!

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

Latrece will keep $135

Step-by-step explanation:

First, if she sold 18 bracelets, then 18 x 4 = 72.

Latrece will give her friend $72, so 207 - 72 = 135.

Hope this helps!

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Please Help ASAP A basketball player shoots a basketball with an initial velocity of 15 ft/sec. The ball is released from an ini
bixtya [17]

Part 1: the function would be

h(t)= -16t^2+15t+6.5

Part 2: using the same steps it stated on the calculator

x=1.26

Part 3: by using t= -b/(2a) 15 as b and -16 as a  makes it

t= 15/32

Part 4: You then put 15/32 in for t in the equation making the maximum height

10.02

IDK IF THIS IS RIGHT BUT IVE SPENT ALL DAY ON THIS

8 0
4 years ago
A manufacturer of precision measuring instruments claims that the standarddeviation in the use of the instruments is less than 0
alexdok [17]

Answer:

i) There is insufficient evidence to support the claim that the standard deviation of the instruments is less than 0.00002 millimeters.

ii) p_v= P(\chi^2_{7}

Step-by-step explanation:

s=0.00001 represent the sample standard deviation

\alpha =0.01 represent the significance level for the test

\sigma_o =0.00002 represent the value that we want to test

n=8 represent the sample size

A chi-square test can be used to test "if the standard deviation of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test".

Null and alternatve hypothesis

The system of hypothesis on this case would be given by:

Null Hypothesis: \sigma \geq 0.00002

Alternative Hypothesis: \sigma

The statistic to test this is given by:

T=(n-1)(\frac{s}{\sigma_0})^2   (1)

Part i) Calculate the statistic

If we replace into formula (1) we got this:

T=(8-1)(\frac{0.00001}{0.00002})^2 =1.75   (1)

The critical region for a for a lower one-tailed alternative is given by

T< \chi^2_{1-\alpha/2,N-1}

The degrees of freedom are given by

df=n-1=8-1=7

And if we use the Chi Square distribution with 7 degrees of freedom we see that \chi^2_{1-0.01/2,7}=1.239

And our critical region would be T< 1.239 so on this case we can conclude that we fail to reject the null hypothesis. So it's not enough evidence to conclude that the population standard deviation is less than 0.00002 mm.

Part ii) Calculate the p value

In order to calculate the p value we can do this:

p_v= P(\chi^2_{7}

If we compare this value with the significance level (0.01) we see that p_v>\alpha

This agrees with the conclusion since when the p values is greater than the significance level we FAIL to reject the null hypothesis, same conclusion as part i).

7 0
3 years ago
Classify the polynomial by degree and number of terms<br> v4 - 3v² +5v + 10
emmainna [20.7K]
Quadratic polynomial with 4 terms is what this is
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2 years ago
Question 8<br> -4(x+5) = 5(x-4)<br> Question 9
alexandr402 [8]

Answer:

x=0 for question 8

Step-by-step explanation:

7 0
3 years ago
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Explain how an outlier with a large value will affect the mean.
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An outlier with a large value will affect the mean by increasing it.
An outlier with a small value will affect the mean by decreasing it.
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