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Zanzabum
3 years ago
10

PEASE HELP ASAP They need to be whole numbers

Physics
2 answers:
Paha777 [63]3 years ago
8 0

Answer:

50 Kilograms Force (kgf) = 50 Kilograms Force (kgf)

100 Kilograms Force (kgf) = 100 Kilograms Force (kgf)

150 Kilograms Force (kgf) = 150 Kilograms Force (kgf)

200 Kilograms Force (kgf) = 200 Kilograms Force (kgf)

Explanation:

Sunny_sXe [5.5K]3 years ago
5 0

Answer:

50n = 10 ms

100n = 20 ms

150n = 30 ms

200n = 40 ms

Explanation: i might be wrong though but im probably 60% or 80% mainly bc my mood is bad so i do lower

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The perceived pitch of a tone is largely determined by its frequency

<h3>What is  frequency ?</h3>

The frequency of a repeated event is its number of instances per unit of time. In some cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated.

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2 years ago
A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm ons tionless bearings. Two 500 g blocks fall from above, hit the tum ble s
Verdich [7]

There are mistakes in the question.The correct question is here

A 2.0 kg, 20-cm-diameter turntable rotates at 100 rpm on frictionless bearings. Two 500 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick. What is the turntable’s angular velocity, in rpm, just after this event?

Answer:

w=50 rpm

Explanation:

Given data

The mass turntable M=2kg

Diameter of the turntable d=20 cm=0.2 m

Angular velocity ω=100 rpm= 100×(2π/60) =10.47 rad/s

Two blocks Mass m=500 g=0.5 kg

To find

Turntable angular velocity

Solution

We can find the angular velocity of the turntable as follow

Lets consider turntable to be disk shape and the blocks to be small as compared to turntable

I_{turntable}w=I_{block1}w^{i}+I_{turntable}w^{i}+I_{block2}w^{i}

where I is moment of inertia

w^{i}=\frac{I_{turntable}w}{I_{block1}w^{i}+I_{block2}w^{i}+I_{turntable}w^{i}}\\   So\\I_{turntable}=M\frac{r^{2} }{2}\\I_{turntable}=2*(\frac{(0.2/2)}{2} )\\ I_{turntable}=0.01 \\And\\I_{block1}=I_{block2}=mr^{2}\\I_{block1}=I_{block2}=(0.5)*(0.2/2)^{2} \\ I_{block1}=I_{block2}==0.005\\so\\w^{i}=\frac{I_{turntable}w}{I_{block1}w^{i}+I_{block2}w^{i}+I_{turntable}w^{i}}\\w^{i}=\frac{0.01*(10.47)}{0.005+0.005+0.01} \\w^{i}=5.235 rad/s\\w^{i}=5.235*(60/2\pi )\\w^{i}=50 rpm

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3 years ago
Which of these examples is NOT a functional group?
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What is the difference between polarization and separation of charge
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HOPE IT HELPS!!!!!!
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