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3 years ago

What kind of mixture is a solution? a colloid ?

Physics

2 answers:

klio [65]3 years ago

6 0

Solute plus solvent, the results is called solution

yarga [219]3 years ago

5 0

A solution is two things mixed together...Like water and sand. The universal solvent is water, so a solution is not a colloid. Solvents take over another compound.

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The planet Uranus has a radius of 25,360 km and a surface acceleration due to gravity of 9.0 m/s^2 at its poles. Its moon Mirand

AlexFokin [52]

Answer:

$8.67791\times 10^{25}\ kg$

$0.34589\ m/s^2$

$0.07903\ m/s^2$

Explanation:

M = Mass of Uranus

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Uranus = 25360 km

h = Altitude = 104000 km

$r_m$ = Radius of Miranda = 236 km

m = Mass of Miranda = $6.6\times 10^{19}\ kg$

Acceleration due to gravity is given by

$g=\dfrac{GM}{r^2}\\\Rightarrow M=\dfrac{gr^2}{G}\\\Rightarrow M=\dfrac{9\times 25360000^2}{6.67\times 10^{-11}}\\\Rightarrow M=8.67791\times 10^{25}\ kg$

The mass of Uranus is $8.67791\times 10^{25}\ kg$

Acceleration is given by

$a_m=\dfrac{GM}{(r+h)^2}\\\Rightarrow a_m=\dfrac{6.67\times 10^{-11}\times 8.67791\times 10^{25}}{(25360000+104000000)^2}\\\Rightarrow a_m=0.34589\ m/s^2$

Miranda's acceleration due to its orbital motion about Uranus is $0.34589\ m/s^2$

On Miranda

$g_m=\dfrac{Gm}{r_m^2}\\\Rightarrow g_m=\dfrac{6.67\times 10^{-11}\times 6.6\times 10^{19}}{236000^2}\\\Rightarrow g_m=0.07903\ m/s^2$

Acceleration due to Miranda's gravity at the surface of Miranda is $0.07903\ m/s^2$

No, both the objects will fall towards Uranus. Also, they are not stationary.

6 0

3 years ago

A window in a house has a rectangular shape of 2.0 m by 1.0 m. The glass in the window is 0.5 cm thick, with a thermal conductiv

KonstantinChe [14]

Answer:

P = 5280 W

Explanation:

The conductivity of the materials determines that heat flows from the hot part to the cold part, the equation for thermal conductivity transfer is

P = Q / t = k A ( $T_{h}$ - $T_{c}$ ) / L

Where k is the thermal conductivity of the glass 0.8 W / ºC, A the area of the window, T the temperature and L is glass thickness

Let's calculate the window area

A = l * a

A = 2.0 1.0

A = 2.0 m²

Let's replace

L = 0.5 cm (1 m / 100 cm) = 0.005 m

P = 0.8 2 (20.5 - 4) / 0.005

P = 5280 W

7 0

3 years ago

A hot air balloon is moving at a speed of 10 meters/second in the +x direction. The balloonist throws a brass ball with a veloci

PIT_PIT [208]

The ball is traveling in the + x direction at 8m per second. After 20 seconds it has moved 160m forward from the spot where it was tossed.

8 0

3 years ago

Consider a steel guitar string of initial length L=1.00L=1.00 meter and cross-sectional area A=0.500A=0.500 square millimeters.

erma4kov [3.2K]

Answer:

The extent to which it would stretch is $\Delta L = 0.015 \ m$

Explanation:

From the question we are told that

The initial length is $L = 1.00m$

The area is $A = 0.500 mm^2 = \frac{0.500}{1 *10^6} = 0.500*10^6 \ m^2$

The Young modulus of the steel is $Y = 2.0*10^{11} Pa$

The tension is $T =1500 N$

The Young modulus is mathematically represented as

$Y = \frac{\sigma}{e}$

Where $\sigma$ is the stress which is mathematically represented as

$\sigma = \frac{F}{A}$

Substituting values

$\sigma = \frac{1500}{0.500*10^{-6}}$

$\sigma = 3.0*10^9 N/m^2$

And e is the strain which is mathematically represented as

$e = \frac{\Delta L}{L }$

Where $\Delta L$ The extension of the steel string

Substituting these into the equation above

$Y = \frac{3.0*10^9}{\frac{\Delta L}{L} }$

Substituting values

$2.0 *10^{11} = \frac{3.0*10^9}{\frac{\Delta L}{L} }$

$\Delta L = \frac{3.0*10^9 * 1}{2.0 *10^{11}}$

$\Delta L = 0.015 \ m$

7 0

3 years ago

What is the maximum energy EmaxEmaxE_max stored in the capacitor at any time during the current oscillations

DanielleElmas [232]

Complete Question

An L-C circuit has an inductance of 0.350 H and a capacitance of 0.290 nF . During the current oscillations, the maximum current in the inductor is 2.00 A .

What is the maximum energy $E_{max}$ stored in the capacitor at any time during the current oscillations?