Ask question

Ask question

All categories

3 years ago

14

When the net force on an object is greater than zero, the object will accelerate in the direction of the ? Force

1 answer:

romanna [79]3 years ago

3 0

<span>When the net force on an object is greater than zero, the object will accelerate in the direction of the applied force. You can also calculate it's magnitude by:
F = m </span>× a

In short, You were right, direction of acceleration will be in the direction of force.

Hope this helps!

You might be interested in

This is my question

baherus [9]

All of the above hope this could
Help!

8 0

3 years ago

Read 2 more answers

One mole of helium atoms has a mass of 4 grams. If a helium atom in a balloon has a kinetic energy of 2.176 × 10^-21J, what is t

Mrrafil [7]

Answer:

$v=1.043\times 10^{-9}\ m/s$

Explanation:

The expression for kinetic energy is:

$K.E.=\frac {1}{2}\times m\times v^2$

K.E. is the kinetic energy = $2.176\times 10^{-21}\ J$

m is the mass = 4 g = 0.004 kg (As 1 g = 0.001 kg)

v is the velocity

Applying values as:

$2.176\times 10^{-21}=\frac{1}{2}\times 0.004\times v^2$

$v^2=\frac{2.176\times 10^{-21}\times 2}{0.004}$

$v=\sqrt{\frac{4.352}{10^{21}\times \:0.004}}$

$v=1.043\times 10^{-9}\ m/s$

8 0

3 years ago

Calculate the potential difference if 20J of energy are transferred by 8C of charge.

grin007 [14]

<h2>v = 2.5J/c</h2>

Explanation:

<h2>Given:</h2>

<h3>Energy = E = 20J</h3>

<h3>Charge = Q = 8C</h3>

<h2>Require :</h2>

___________

<h3>Potential Difference = V = ?</h3>

<h2>Formula :</h2>

____________

<h2>V = $\frac{E}{Q}$ </h2>

<h2>Solution:</h2><h3>_________</h3>

<h2>V = $\frac{20J}{8C}$ </h2>

<h3>V = 2.5V</h3>

.

.

.

<h2> $\color{Red}{Mark - Brainliest}$ </h2>

4 0

3 years ago

Which of the following is a contact force?

liberstina [14]

Air resistance is type of contact force as the air should be in contact with the surface of moving

object to ocure air resistance.

6 0

3 years ago

A potter’s wheel of radius 17 cm starts from rest and rotates with constant angular acceleration until at the end of 32 s it is

dedylja [7]

Answer:

α=0.625rad/s^2

v=340m/s

w=10rad/s

θ=320rad

Explanation:

Constant angular acceleration = ∆w/∆t

angular acceleration = 20/32

α=0.625rad/s^2

Linear velocity v=wr

v = 20×17= 340m/s

Average angular velocity

w0+w1/2

w= 0+20/2

w= 20/2

w=10rad/s

What angle did it rotate with

θ=wt

θ= 10×32

=320rad

4 0

3 years ago