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OLEGan [10]
4 years ago
6

Identify the type of wave produced by light

Physics
2 answers:
anyanavicka [17]4 years ago
7 0

Electromagnetic waves are produced by light. They are made up of oscillating magnetic and electric fields. They include radio waves, microwaves,infrared waves, visible light, ultraviolet, x-rays and gamma rays. Electromagnetic waves carry energy.  radio waves are used in communications to send signals from one place to another.Microwaves use high energy that increases the motion of molecules in your food. Infrared waves are used in things like night vision cameras or a tv remote. The human body has a temperature that produces radiation which can be picked up by an infrareds device.Ultraviolet light ( like from the sun) can cause sunburn and skin cancer .  That.s why it’s important to wear sunscreen and sunglasses to protect our bodies and and our eyes. X-rays are very high energy and like ultraviolet rays can cause damage to the body. But x-rays used at the right amount can be safe on the tissues and organs in our bodies.   Hope this helps !

tamaranim1 [39]4 years ago
4 0

Light <u>IS</u> electromagnetic waves.  

"Light" is any electromagnetic wave that you KNOW about when it gets into your eye.  There are a lot of other electromagnetic waves that you DON't know about even if they get into your eye, because they're longer or shorter than what your eye can detect.  Those are radio waves, microwaves, heat waves, ultraviolet waves, X-rays, and gamma rays.  They're all the same thing as light, but they have wavelengths that our eyes can't detect.

Our eyes can detect a "band" of wavelengths in a range of about 2 to 1 ... the longest wavelengths we can see are about twice as long as the shortest ones we can see.  

When we see different wavelengths, they look like different colors.  

-- The longest light waves we can see are around 32.6 thousand in         1 inch, and they look deep red.  

-- The shortest light waves we can see are around 65 thousand in          1 inch, and they look bright violet.

ALL of the other colors that humans can see are in between those limits.

When ALL colors of light get into your eye at the same time, the light looks WHITE.

You might be interested in
The four lines observed in the visible emission spectrum of hydrogen tell us that
Gemiola [76]

Answer:

The correct answer is violet, blue, green, and red emission lines.

Explanation:

When samples of pure elements are heated they emit a continuous spectrum of electromagnetic radiation. When elements are heated at very high temperatures, the electrons get excited and they jump to consequent orbits and this results in transmission of electromagnetic radiation. The four lines visible in the emission spectrum of hydrogen are violet, blue, green, and red, the most intense of which is at 656 nanometre.

7 0
3 years ago
What type of decay has the release of electromagnetic energy from the nucleus and has the most penatrating power through other s
Verdich [7]

Answer:

Gamma decay

Explanation:

There are 3 types of radioactive decay:

- Alpha decay: in this decay, a nucleus emits an alpha particle (consisting of 2 protons and 2 neutrons, so a nucleus of helium). The alpha particle has a large charge (2e) and a large mass (4u), so it is strongly ionizing, and therefore loses energy faster while moving through matter, therefore its penetrating power is low (it can be easily stopped by a thin sheet of paper or by the skin)

- Beta decay: this decay occurs when a neutron in a nucleus turns into a proton, emitting a beta particle (a fast-moving electron) alongside with an antineutrino. The beta particle has a lower charge (e) and a smaller mass than the alpha particle, so it has a moderate penetrating power, being able to penetrate more than the alpha particle (the beta particle can be stopped by a thin sheet of aluminium)

- Gamma decay: this decay occurs when an excited nucleus decays emitting a gamma ray photon (which is electromagnetic energy with very high energy and frequency). The gamma ray photon has no charge and no mass, therefore it has the most penetrating power, being able to travel a much large distance before being absorbed by matter (several metres of concrete are required to stop gamma radiation.

So, the description in the question refers to gamma decay.

7 0
3 years ago
1.A Radio station broadcasts modern song on medium wave 350 Hz every day at ten o’clock in the morning. The velocity of radio wa
love history [14]

Answer:

ans \:  = \boxed{{4.8 \times 10}^{ - 4}  Hz}

Explanation:

given \to \\  f_{r} = 350 \:  \\ v_{r} =  {3 \times 10}^{8}  \\ but \to \\ v = f \gamma   \to \:  \gamma  =  \frac{v}{f}  : hence \to \\  \gamma _{r} =  \frac{v_{r}}{f_{r}}   =  \frac{3 \times 10^{8} }{350}   =  \boxed{857,142.85714 \: m}\\ therefore \to \\ given \to \\  f_{w} = water \: frequency = \:  \boxed{  ?}\:  \\ v_{w} =  14 50 \\ but \to \\ v = f \gamma   \to \:  \gamma  =  \frac{v}{f}  : hence \to \\  \gamma _{w} =  \frac{v_{w}}{f_{w}}   =  \frac{1}{100}  \times \gamma _{r}  =  \frac{1}{100}  \times 857,142.85714  \\\gamma _{w}  =  \boxed{8,571.4285714 \: m} : hence \to \:  \\ f_{w} =  \frac{v_{w}}{ \gamma _{w}}  =  \frac{1450}{8,571.4285714}  =  \boxed{0.1691666667} \\ if \: the \: number \: of \: times = \boxed{ x} \\ f_{r} (x)=f_{w} \\ (x) =  \frac{f_{w}}{f_{r}}  =  \frac{0.1691666667}{350}  = 0.0004833333 \\ hence \to \\ the  \: frequency  \: of \:  the \:  radio  \: wave  \: is \to \:   \boxed{{4.8 \times 10}^{ - 4}  }\:  \\ that  \: of  \: the \:  wave  \: created  \: in  \: the  \: water.

♨Rage♨

8 0
3 years ago
A 13,900 N car traveling at 40.0 km/h rounds a curve of radius 1.80 ✕ 102 m.
miss Akunina [59]

a) 0.68 m/s^2

b) 964.5 N

c) 0.069

Explanation:

a)

When an object is moving in a circular motion, the direction of its velocity is changing - therefore, it has an acceleration towards the center of the circle, called centripetal acceleration.

The magnitude of the centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circle

For the car in this problem:

v = 40.0 km/h = 11.1 m/s is the speed

r = 180 m is the radius of the circle

Substituting, we find the acceleration:

a=\frac{11.1^2}{180}=0.68 m/s^2

b)

The centripetal force is the force that keeps the object along its circular motion. It also acts towards the center of the circle, and it is given by

F=ma

where

m is the mass of the object

a is the centripetal acceleration

Here the weight of the car is

W=mg=13,900 N

where

g=9.8 m/s^2 is the acceleration due to gravity

So the mass is

m=\frac{W}{g}=\frac{13,900}{9.8}=1418.4 kg

Therefore, the centripetal force is

F=(1418.4)(0.68)=964.5 N

c)

In this case, the force of static friction between the tires and the road provides the required centripetal force to keep the car in circular motion. This force is given by:

F_f=\mu mg

where

\mu is the coefficient of friction

Equating the frictional force to the centripetal force,

\mu mg=ma

So we get:

\mu=\frac{a}{g}

And substitutng:

a=0.68 m/s^2 (centripetal acceleration)

g=9.8 m/s^2

We find:

\mu=\frac{0.68}{9.8}=0.069

4 0
3 years ago
Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s.
rjkz [21]

Answer:

Momentum of block B after collision =-50\ kg\ ms^{-1}

Explanation:

Given

Before collision:

Momentum of block A = p_{A1}= -100\ kg\ ms^{-1}

Momentum of block B = p_{B1}= -150\ kg\ ms^{-1}

After collision:

Momentum of block A = p_{A2}= -200\ kg\ ms^{-1}

Applying law of conservation of momentum to find momentum of block B after collision p_{B2}.

p_{A1}+p_{B1}=p_{A2}+p_{B2}

Plugging in the given values and simplifying.

-100-150=-200+p_{B2}

-250=-200+p_{B2}

Adding 200 to both sides.

200-250=-200+p_{B2}+200

-50=p_{B2}

∴ p_{B2}=-50\ kg\ ms^{-1}

Momentum of block B after collision =-50\ kg\ ms^{-1}

6 0
3 years ago
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