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2 years ago

Please help with the bottom questions not filled in <3

Mathematics

1 answer:

bezimeni [28]2 years ago

4 0

Answer:

Given below

Step-by-step explanation:

y = 4 , m = -1 , x = 2

y = mx + b

4 = -1 (2) + b

4 = -2 + b

6 = b

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Can someone tell me<br> How to solve this and a explanation?

Evgesh-ka [11]

Answer:

Step-by-step explanation:

Okay so on Saturday there is a 30% sale plus she comes early so +10% and that makes 40% off.

10% of 400=40

multiply by 4 to get 40%, 40*4=40%

40%=160

400-160=240

Hope this helps

6 0

3 years ago

Read 2 more answers

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation

just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation $v(t)= 6t^2-18t+12$ . We are asked to find the distance that the particle will travel in its first 2 seconds.

$s(t)=\int |v(t)|dt$

$s(t)=\int\limits^2_0 |6t^2-18t+12|dt$

Now, we will eliminate the absolute value sign as:

$s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt$

$s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1$

$s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1$

$s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))$

$s(2)=2-9+12-(0)-16+36-24-(-2+9-12)$

$s(2)=5-(0)-4-(-5)$

$s(2)=5-4+5$

$s(2)=6$

Therefore, the particle will travel 6 feet in first 2 seconds.

7 0

3 years ago

I will give brainilest

den301095 [7]

Answer:

63°

Step-by-step explanation:

Vertical angles are equal to each other.

8 0

2 years ago

(3.1 x 10^5) (.00000432)

Ber [7]

Answer:

13.392

Step-by-step explanation:

(3.1×1000000)(.00000432)

7 0

3 years ago

1/3×24 to the power of 2 times 30

svp [43]

1/3*(24^2)*30=5760

Any questions just ask. Thanks

4 0

3 years ago