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3 years ago

190258.50,152698.00, 122753.00, 220523.00, 231951.00 what is the average of these five amounts?

Mathematics

2 answers:

White raven [17]3 years ago

7 0

1563654344.40
..........................

sveta [45]3 years ago

5 0

<span>183636.7

I hope this is right and helps ^-^</span>

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Which of the following lines is parallel to the line y = 4x - 6?

Dovator [93]

Answer:

d y=4x + 5

Step-by-step explanation:

Is parallel beacause they have the same slope, remember

y=ax + c

where a is the slope of the line

8 0

3 years ago

An online furniture store sells chairs for $150 each and tables for $400 each. Every day, the store can ship no more than 30 pie

ivolga24 [154]

Answer:

minimum of 13 chairs must be sold to reach a target of $6500

and a max of 20 chairs can be solved.

Step-by-step explanation:

Given that:

Price of chair = $150

Price of table = $400

Let the number of chairs be denoted by c and tables by t,

According to given condition:

t + c = 30 ----------- eq1

t(150) + c(400) = 6500 ------ eq2

Given that:

10 tables were sold so:

t = 10

Putting in eq1

c = 20 (max)

As the minimum target is $6500 so from eq2

10(150) + 400c = 6500

400c = 6500 - 1500

400c = 5000

c = 5000/400

c = 12.5

by rounding off

c = 13

So a minimum of 13 chairs must be sold to reach a target of $6500

i hope it will help you!

4 0

3 years ago

Can someone help me solve this problem by factoring.<br> x^2 + 8x + 16 = 0

Pavlova-9 [17]

Factorization: (x + 4)∧2=0

Solutions based on Factorization: x + 4 = 0 ⇒ X∨1 = X∨2 = -4

8 0

4 years ago

Read 2 more answers

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of the line that passes through (−12, 15) and (4, −5) is

$m_{1} = \frac{ - 5 - 15}{4 - - 12}$

$m_{1} = \frac{ - 20}{16} = - \frac{5}{4}$

The slope of the line going through (−8, −9) and (16, 21) is

$m_{2} = \frac{21 - - 9}{16 - - 8}$

$m_{2} = \frac{21 + 9}{16 + 8}$

$m_{2} = \frac{30}{24} = \frac{5}{4}$

The product of the two slopes is

$m_{1} \times m_{2} = - \frac{4}{5} \times \frac{5}{4} = - 1$

Since

$m_{1} \times m_{2} = - 1$

the two lines are perpendicular.

4 0

3 years ago

Read 2 more answers

Find the equation of the perpendicular bisector of a line segment whose end points are (-3,9) and (-1,5)

timofeeve [1]

First find the equation of y.

$y=mx+n=\frac{\Delta y}{\Delta x}x+n$

Find the slope m.

$m=\frac{5-9}{-1-3}=\frac{-4}{-4}=1$ .

Pick one point, I'll pick (-3, 9). Insert coordinates in equation then compute n.

$9=1(-3)+n\implies n=12$ .

The equation of a line y is:

$y=x+12$ .

The perpendicular line $y_{\perp}$ is same like the normal line except its slope m becomes:

$k=-\frac{1}{m}=-1$ .

The equation of a perpendicular bisector is thus:

$y_{\perp}=-x+12$ .

Hope this helps.

6 0

3 years ago

Read 2 more answers