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s344n2d4d5 [400]
2 years ago
10

Pam works a 52 hours in a week. Considering that a normal work week is 40 hours and paid at $1470 per hour and overtime is paid

at time and a quarter
What is her basic wage ?


How much is she paid in overtime wages? (SHOW WORK) *


What is her gross wage ?
Mathematics
1 answer:
Bezzdna [24]2 years ago
6 0

Step-by-step explanation:

they way it is written, she has one of the best paying jobs in the world : $1470 per hour ...

but I guess it is really $14.70 per hour, right ?

that is then her basic wage : $14.70 per hour for 40 hours = 14.7 × 40 = $588.

her overtime rate is then 14.7×1.25 (one time and a quarter) = 18.375 ≈ $18.38

and she gets that rate for all hours beyond the basic 40 hours, so, 52-40 = 12 hours.

12×18.38 = $220.56

or if you need it totally precise

12×18.375 = $220.50

in total, her gross wage for that week is then

588 + 220.56 = $808.56

or totally precise with unrounded hourly rates

588 + 220.5 = $808.50

which would create a mean hourly rate

808.56/52 = $15.54923077... per hour ≈ $15.55 per hour

or

808.5/52 = $15.54807692... per hour ≈ $15.55 per hour

many payroll systems do the rounding of the hourly rates and then calculate the total amount (as the first option here). some others keep the full decimal positions in the calculation and then only round the total (as the second option here).

so, it is the question what your teacher expects here. I cannot tell from the description.

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Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
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Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

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Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

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