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3 years ago

Given z1=9+9sqrt(3)i and z2=2+sqrt(3)i what is z2-z1 This is urgent will give brainliest!

Mathematics

1 answer:

icang [17]3 years ago

3 0

Answer:

$= 2 + \sqrt{3} i - (9 + 9 \sqrt{3} i) \\ = (2 - 9) + ( \sqrt{3} - 9 \sqrt{3} )i \\ = - 7 + (1 - 9) \sqrt{3} i \\ = - 7 - 8 \sqrt{3} i$

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I need help with a math problem, question was deleted from some bh mod but image below

Elis [28]

The y intercept is 1.

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2 years ago

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Write the monomial in standard form. name it's coefficient and identify its degree.

Hunter-Best [27]

Answer:

$Standard\ Form = {3n^2} m^{-2}$

Step-by-step explanation:

Given

$\frac{2}{3m^2n} * 4.5n^3$

Required

Write in Standard Form

To start with; the two monomials have to be multiplied together;

$\frac{2}{3m^2n} * 4.5n^3$

$Standard\ Form = \frac{2 * 4.5n^3}{3m^2n}$

Split the numerator and the denominator

$Standard\ Form = \frac{2 * 4.5 * n^3}{3 * m^2 * n}$

Multiply Like terms

$Standard\ Form = \frac{9 * n^3}{3 * m^2 * n}$

Divide 9 by 3 to give 3

$Standard\ Form = \frac{3 * n^3}{m^2 * n}$

Divide n³ by n to n²

$Standard\ Form = \frac{3 * n^2}{m^2 }$

Split fraction

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$

From laws of indices;

$\frac{1}{a^n} = a^{-n}$

$Standard\ Form = {3 * n^2} * \frac{1}{m^2 }$ becomes

$Standard\ Form = {3 * n^2} * m^{-2}$

Multiply all together

$Standard\ Form = {3n^2} m^{-2}$

5 0

3 years ago

if the unit price for oranges is $0.26 per pound and Jim pays $2.08 for oranges, how many puns of oranges does he buy? A) 4.5 po

Nata [24]

Hey there!

If the price per orange is $.26 and we want to know how many oranges he bought and we have our total, we can set o equal to how many oranges he got and set up an algebraic equation:

0.26o = 2.08

We multiply .26 by o because o is how many oranges he bought and that's what we're solving for- so we multiply by the unit price.

To isolate o, we divide both sides by .26 to get:

The answer is C- Jim bought 8 oranges.

Hope this helps!

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3 years ago

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Which of the following shows the division problem below in synthetic division form? (6x^3+x^2-3)/(x-7)

PSYCHO15rus [73]

Answer:

Option C.

Step-by-step explanation:

If a polynomial P(x) is divided by (x-c), then we write leading coefficients inside the synthetic division line and c outside the synthetic division line.

The given division problem is

$\dfrac{6x^3+x^2-3}{x-7}$

Here,

$x-c=x-7\Rightarrow c=7$

The numerator polynomial can be written as

$P(x)=6x^3+x^2+0x-3$

So, the coefficients of numerator are 6, 1, 0, -3.

The synthetic division form for given division problem is

7 | 6 1 0 -3

Therefore, the correct option is C.

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3 years ago

Cos(x+y)/cos(x)sin(y)=cot(y)-tan(x)

zhuklara [117]

So there is an identity we'll need to use to solve this:

cos(x+y) = cosxcosy - sinxsiny

replace the numerator with the right hand side of that identity and we get:

(cosxcosy - sinxsiny)/cosxsiny

Separate the numerator into 2 fractions and we get:

cosxcosycosxsiny- sinxsiny/cosxsiny

the cosx's cancel on the left fraction, the siny's cancel on the right fraction and we're left with:

cosy/siny - sinx/cosx

which simplifies to:

coty - tanx

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3 years ago