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zysi [14]
3 years ago
8

Plz Help me!!! will mark brainliest!!

Mathematics
1 answer:
Ksju [112]3 years ago
6 0

Answer:

3x² * (6x² + 4x - 8) = 18x⁴ + 12x³ - 24x²

2x * (9x³ + 6x² - 12x) = 18x⁴ + 12x³ - 24x²

x² * (18x² + 12x - 24) = 18x⁴ + 12x³ - 24x²

6x² * (3x² + 2x - 4) = 18x⁴ + 12x³ - 24x²

Step-by-step explanatation:

Let's set unknown variables as y (and y₁, y₂, etc)

Question 1:

y *  (6x² + 4x - 8) = 18x⁴ + 12x³ - 24x²

So, divide both sides by (6x² + 4x - 8)

y = 3x²

Question 2:

2x * (9x^y₁ + y₂*x^y₃ - y₄*x) = 18x⁴ + 12x³ - 24x² '

Divide both sides by 2x.

(9x^y₁ + y₂*x^y₃ - y₄*x) = 9x³ + 6x² -12x

y₁ = 3, y₂ = 6, y₃ = 2, y₄ = 12

Question 3:

x^y * (18x² + 12x - 24) = 18x⁴ + 12x³ - 24x²

Divide both sides by (18x² + 12x - 24)

x^y = x²

Question 4:

y₁  * x^y₂ * (3x² + 2x - 4) = 18x⁴ + 12x³ - 24x²

Divide both sides by (3x² + 2x - 4)

y₁  * x^y₂ = 6x²

y₁ = 6, y₂ = 2

I hope this helps! Feel free to ask any questions!

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Read 2 more answers
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

7 0
4 years ago
The area of cross section of a prism is 45cm² and its height is,10cm. Find its volume​
mrs_skeptik [129]

Answer:

The Volume of triangular prism

                     V = 450 cm³

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given The area of cross section of a prism A = 45cm²

and     height (h) = 10 cm

The Volume of triangular prism

                V = ( Base area X Height )

                    =  45 X 10

                    = 450 cm³

The Volume of triangular prism

                     V = 450 cm³

6 0
3 years ago
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