17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
Supplementary adjacent angles form a "linear pair." Together, they make a line. The angle supplementary to 85° will be slightly obtuse, just as 85° is slightly acute.
Answer:
see explanation
Step-by-step explanation:
Note that cos315° = cos45° and sin315° = - sin45° and
cos45° = sin45° = 
= 
Hence
12(cos315° + isin315°)
= 12(cos45° - isin45°)
= 12( - i )
= 6
- 6i
Answer:
f(x) = ( 1/3) ^ (x)
Step-by-step explanation:
The function is
f(x) = (1/3) ^ (x)
When x = 1 f(x) = 1/3
when x=2 f(x) = 1/9
When x = -1 f(x) = ( 1/3) ^ -1 = 3/1 =3
Answer:
what is the question and give the question first
