Explain how to construct a perpendicular bisector. ?

2 answers:

8 0

Open the compass it is more than half of the distance between a and b, and scribes arcs of the same radius centered at a and b. call the two points where these two arcs meet c and d. Draw the line between c and d. CD it is the perpendicular bisector of the line segment AB. call the point where CD intersects AB and E

defon2 years ago

8 0

First: place the compass on the end of a line segment. second: adjust the compass to just slightly longer than half the line segment length. third: draw arcs above and below the line fourth: keeping the same compass width draw arcs from the other end of the line. last place ruler where arcs cross and draw line segment

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A plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph. after sometime and flight, space the p

ratelena [41]

The speed of the plane after it encounters the wind is C.285mph

<h3>How to calculate the speed of the plane when it encounters the wind?</h3>

Since the plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph it's velocity is v = (320cos270°)i + (320sin270°)j

= (320 × 0)i + (320 × -1)j

= 0i - 320j

= - 320j mph

Also, the plane encounters a 35 mph wind blowing directly north. The velocity of the wind is v' = 35j mph

So, the velocity of the plane after it encounters the wind is the resultant velocity, V = v + v'

= -320j mph + 35j mph

= -285j mph

So, the speed of the plane after it encounters the wind is the magnitude of V = |-285j| mph

= 285 mph

So, the speed of the plane after it encounters the wind is C.285mph

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