8,991 which is the product of 999 times 9
Since you are given that the student registered early, the total number you deal with is all students who registered early.
211 + 329 = 540
number of undergraduates who registered early = 211
Among students who registered early:
p(undergraduate) = 211/540
Hi!
7 + (-3) = 7 - 3 = 4
The correct answer is C.) 4.
Hope this helps!
Hey there!
When we're adding with different denominators, our goal is to keep the equivalent fraction, but create like denominators.
Let's think of an easier situation. If we have the number 5 and we want an equivalent number, we multiply by one. It's no different with fractions. We want to multiply by some version of one, like 2/2 or 4/4
For example, if we have:
2/8 + 4/6
Our LCM is 24. Therefore, we multiply 2/8 by 3/3:
2/8(3/3) = 6/24
And 4/6 by 4/4:
4/6(4/4) = 16/24
As you can see, we multiplied by versions of 1, so they're still the same fraction.
We have:
16/24 + 6/24 = 22/24 = 11/12
Hope this helps!
