maximum speed of cheetah is

speed of gazelle is given as

Now the relative speed of Cheetah with respect to Gazelle


now the relative distance between Cheetah and Gazelle is given initially as "d"
now the time taken by Cheetah to catch the Gazelle is given as

so by rearranging the terms we can say


so above is the relation between all given variable
Answer:
-5 m/s^2
Explanation:
10/2=5 and is is a stop so it is negitive
Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy


=37.4mpy
mm/yr


=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
The frequency of an oscillation is equal to the reciprocal of the period:

where
f is the frequency
T is the period
In our problem, the period is T=8.01 s, therefore the corresponding frequency is
First recall the equation that relates frequency to wavelength:
v = fw
Note that the v is the speed of light, a constant. Now plug in the information we know!
(3×10^8) = (6.67 × 10^14) w
Hit the numbers on the calculator and you'll get the wavelength, w. If you comment your answer I'll check it for you. :)