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adelina 88 [10]
3 years ago
5

Various radial points on a rotating Ferris wheel have: I. different linear velocities II. different angular velocities III. equa

l linear velocities IV. equal angular velocities
Physics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

I) True,  II) False,  III) False,  IV) True    

Explanation:

In this exercise, it is asked to answer different statements, for this we will use the relationship between angular and linear velocity

           v = w r

let's review the claims

I) True. From the initial equation we see that the linear velocity depends on the radius

II) False. All points rotate with the same angular velocity

III) False. Linear velocity changes with radius

IV) True. The angular velocity of all points is the same

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25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression
levacccp [35]

maximum speed of cheetah is

v_1 = v_{max}

speed of gazelle is given as

v_2 = v_{g}

Now the relative speed of Cheetah with respect to Gazelle

v_{12} = v_1 - v_2

v_{12} = v_{max} - v_g

now the relative distance between Cheetah and Gazelle is given initially as "d"

now the time taken by Cheetah to catch the Gazelle is given as

d = v_{12}* t

so by rearranging the terms we can say

t = \frac{d}{v_{12}}

t = \frac{d}{v_{max} - v_g}

so above is the relation between all given variable

6 0
4 years ago
Find the deceleration of<br> a cyclist who comes to<br> rest from 10m/s in 2<br> seconds.
I am Lyosha [343]

Answer:

-5 m/s^2

Explanation:

10/2=5 and is is a stop so it is negitive

5 0
3 years ago
A thick steel sheet of area 100 in.2 is exposed to air near the ocean. After a one-year period it was found to experience a weig
vladimir1956 [14]

Answer:

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

Explanation:

The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is

CPR=\frac{KW}{DAT}

K= constant depends on the system of units used.

W= weight =485 g

D= density =7.9 g/cm³

A = exposed specimen area =100 in² =6.452 cm²

K=534 to give CPR in mpy

K=87.6  to give CPR in mm/yr

mpy

CPR=\frac{KW}{DAT}

        =\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}

        =37.4mpy

mm/yr

CPR=\frac{KW}{DAT}

        =\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}

       =0.952 mm/yr

Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.

3 0
4 years ago
What is the frequency corresponding to a period of 8.01 s?
masha68 [24]
The frequency of an oscillation is equal to the reciprocal of the period:
f= \frac{1}{T}
where
f is the frequency
T is the period

In our problem, the period is T=8.01 s, therefore the corresponding frequency is
f= \frac{1}{8.01 s}=0.12 s^{-1} = 0.12 Hz
8 0
3 years ago
Blue light has a typical frequency of 6.67 x 10 14 1014 Hz. What is the wavelength associated with this frequency?
DerKrebs [107]
First recall the equation that relates frequency to wavelength:

v = fw

Note that the v is the speed of light, a constant. Now plug in the information we know!

(3×10^8) = (6.67 × 10^14) w

Hit the numbers on the calculator and you'll get the wavelength, w. If you comment your answer I'll check it for you. :)

5 0
4 years ago
Read 2 more answers
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