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A man applies a torque to a nut with a wrench 0.350 m long. Because of the cramped space, he must exert a force upward at an ang
1 answer:
Answer:
Explanation:
It is a problem to find the torque but the force applied was performed angularly. In this way the only component that will serve us is the one found in the line of rotation of the object.
Since the force is realized from upward with respect to a line from the bolt through the end of the wrench, we have the component described by Sin (\ theta). The force is performed on the opposite side of the angle, then
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Explanation:
Given
initial velocity(v_0)=1.72 m/s
using
Where v=final velocity (Here v=0)
u=initial velocity(1.72 m/s)
a=acceleration
s=distance traveled
s=0.214 m
(b)time taken to travel 0.214 m
v=u+at
t=0.249 s
(c)Speed of the block at bottom
Here u=0 as it started coming downward
v=1.72 m/s
Answer:
a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s
Explanation:
a)
- As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
- This means that we can use the kinematic equations for displacements along both axes.
- In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:
- In the y-direction, as no acceleration is acting on the skateboarder, we can write the following displacement equation:
- For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:
b)
- From (2) we can get the position on the y-axis (displacement from the origin) as follows:
c)
- In the x- direction, we can find the component of the velocity along this direction, as follows:
- Replacing by the values, we have:
d)
- As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we have:
vfy = voy = -4 m/s