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alina1380 [7]
3 years ago
10

Increased Points to 20. Please Answer.

Mathematics
2 answers:
professor190 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

f, e, and b

Vera_Pavlovna [14]3 years ago
3 0

Answer:

c,f,b,

Step-by-step explanation:

They all equal 5/17

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. To test H0: m = 105 versus H1: m ≠ 105, a simple random sample of size n = 35 is obtained. (a) Does the population have to be
sp2606 [1]

Answer:

A.) No

B.) test statistic = - 3.108

Check explanation

Step-by-step explanation:

H0: m = 105 versus H1: m ≠ 105

Sample size, n = 35, since we have a large sample size, greater than 30.

B.)

xbar = 101.9 ; s = 5.9

Test statistic :

T = (xbar - μ) ÷ (s/√n)

T = (101.9 - 105) / (5.9/√35)

T = - 3.1 / 0.9972820

Test statistic = - 3.11

Pvalue from Tstatistic, df = 34

Pvalue = 0.003772( Pvalue calculator)

Pvalue is the probability of obtaining a value more extreme or exactly that of the test statistic.

At α = 0.01

Pvalue < α ; We fail to reject the Null

7 0
3 years ago
How many radians is -135°? -1/4pie 3/4pie -3/4pie -4/3pie
FrozenT [24]

Answer:

hello :

- 3π/4  = (-3×180°)/4 =  - 540°/4 = - 135°


Step-by-step explanation:


7 0
4 years ago
Read 2 more answers
What is the value of x?
bixtya [17]

oh my god you are such a god level hut

6 0
3 years ago
Read 2 more answers
Is 5 + 2y = 13 a linear relationship?
pychu [463]
No. 
A linear relationship requires an x and y component that are directly proportional. Here, there is only one y value which makes the statement correct. So, you will have a single point on the graph. 
7 0
4 years ago
Which statement about square root x-5 - square root x = 5 is true?
Musya8 [376]
Hello,

Answer D

\sqrt{x-5} - \sqrt{x} =5
==>(x-5) -2*\sqrt{(x-5)x}+x =25
==>2x-30=\sqrt{x(x-5)}
==>x-15=\sqrt{x(x-5)}
==>x^2-30x+225=x(x-5)
==>225=-5x+30x
==>25x=225
==>x=9
But:

\sqrt{9-5} - \sqrt{9}=\sqrt{4} - \sqrt{9}=2-3=-1≠5

Explanation:

\lim_{x \to \infty}  \sqrt{x-5}- \sqrt{x}&#10;&#10;

= \lim_{x \to \infty}   \frac{(\sqrt{x-5}- \sqrt{x})*(\sqrt{x-5}+ \sqrt{x})}&#10;{\sqrt{x-5}+ \sqrt{x}}

= \lim_{x \to \infty}   \frac{(-5)}{\sqrt{x-5}+ \sqrt{x}}

= \lim_{x \to \infty}   \frac{-5}{\infty}=0&#10;&#10;&#10;

7 0
3 years ago
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