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hichkok12 [17]
3 years ago
6

Exponential functions

Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer:

36, 6, (1/)36

1/6 ^ -2 = 6^2 = 36

1/6 ^ -1 = 6^1 = 6

1/6 ^2 = 1/36

WARRIOR [948]3 years ago
5 0

Answer:

oh no i dunno how to do this

Step-by-step explanation:

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Jordan traveled from Seattle to New York City. First, he flew 1,735 miles from Seattle to Chicago. Then he drove 673 miles from
astra-53 [7]
The answer would D just add 1,735+673=2,408
8 0
3 years ago
Read 2 more answers
The perimeter of a rectangular plot is 36 metres. The length is 6 metres more than the width. What is the area of the rectangula
Dmitry_Shevchenko [17]

Answer:

72 m^2

Step-by-step explanation:

Perimeter = 36

Length + width = 18

w + w + 6 = 18

2w + 6 = 18

2w = 12

w = 6

Length + 6 = 18

Length = 12

Area = 6 * 12 = 72 m^2

8 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Please answer the ixl math problem for 15 points and please fill in the blanks with the correct answer please i beg will mark br
aivan3 [116]

Answer:

y = 5x + 4

Step-by-step explanation:

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5 0
3 years ago
10 points! How do I factor 8x^2-26x+15
Rufina [12.5K]
<h3><u>(2x - 5)(4x - 3)</u></h3>

The AC method, also known as splitting the middle, can be shown like this:

8x^2 - 26x + 15

<em><u>Check factors of 120.</u></em>

1 * 120

-1 * -120

2 * 60

-2 * -60

3 * 40

-3 * -40

5 * 24

-5 * -24

6 * 20

-6 * -20 (these factors, when added together, are equal to the middle term, and thus splitting the middle term is possible.)

<em><u>Split the middle term.</u></em>

8x^2 - 6x - 20x + 15

<em><u>Group in terms of 2.</u></em>

(8x^2 - 6x) - (20x + 15)

<em><u>Factor each binomial.</u></em>

2x(4x - 3) - 5(4x - 3)

<em><u>Rearrange the terms.</u></em>

(2x - 5)(4x - 3)

6 0
3 years ago
Read 2 more answers
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