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Andrei [34K]
4 years ago
15

0.5 percent of what number is 3

Mathematics
2 answers:
MAVERICK [17]4 years ago
8 0
600. Hope this helped! :D
sdas [7]4 years ago
7 0
0.5/100 * X= 3
X=3 * 100/0.5 = 300 / 0.5 = 600
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Solve.<br><br> 10x + 16 &gt; 6x + 20
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X>1 is the answer
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4x > 4
x > 1
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Tia is 8 years younger than her sister Annette. Annette is y years old. Write an algebraic expression that describes Tia’s age.
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A rectangle has a<br> perimeter of 20 cm.<br> Its longest side is 6 cm.<br> What is its area?
melamori03 [73]

Answer:

\boxed {24 cm^{2}}

Step-by-step explanation:

<u>Finding the smaller side</u> :

⇒ P = 2(l + w)

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vlabodo [156]

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8 0
3 years ago
Solve the problem, calculate the line integral of f along h
Over [174]
The curve \mathcal H is parameterized by

\begin{cases}X(t)=R\cos t\\Y(t)=R\sin t\\Z(t)=Pt\end{cases}

so in the line integral, we have

\displaystyle\int_{\mathcal H}f(x,y,z)\,\mathrm ds=\int_{t=0}^{t=2\pi}f(X(t),Y(t),Z(t))\sqrt{\left(\frac{\mathrm dX}{\mathrm dt}\right)^2+\left(\frac{\mathrm dY}{\mathrm dt}\right)^2+\left(\frac{\mathrm dZ}{\mathrm dt}\right)^2}\,\mathrm dt
=\displaystyle\int_0^{2\pi}Y(t)^2\sqrt{(-R\sin t)^2+(R\cos t)^2+P^2}\,\mathrm dt
=\displaystyle\int_0^{2\pi}R^2\sin^2t\sqrt{R^2+P^2}\,\mathrm dt
=\displaystyle\frac{R^2\sqrt{R^2+P^2}}2\int_0^{2\pi}(1-\cos2t)\,\mathrm dt
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You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function f:\mathbb R^n\to\mathbb R, we have gradient \nabla f:\mathbb R^n\to\mathbb R^n. The theorem itself then says that the line integral of \nabla f(x,y,z)=\mathbf f(x,y,z) along a curve C parameterized by \mathbf r(t), where a\le t\le b, is given by

\displaystyle\int_C\mathbf f(x,y,z)\,\mathrm d\mathbf r=f(\mathbf r(b))-f(\mathbf r(a))

Specifically, in order for this theorem to even be considered in the first place, we would need to be integrating with respect to a vector field.

But this isn't the case: we're integrating f(x,y,z)=y^2, a scalar function.
7 0
3 years ago
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